All categories

3 years ago

A rectangle has a perimeter of 30. It is dilated by a scale factor of 2.

Mathematics

1 answer:

LuckyWell [14K]3 years ago

5 0

Answer:

It is 60.

Step-by-step explanation:

When shapes are dilated (when they get bigger or smaller), perimeter changes linearly—in direct proportion with length. This means if the scale factor is 2, then you multiply it by 2. 2 multiplied by 30 equals 60.

You might be interested in

Solve. 2a + 3b = 5 6= a -5 a = 4 b = -1 1 a = 6 b=1 a=6 6 = -1 a=4 6 = 1

slamgirl [31]

Answer:Solve. 2a + 3b = 5 6= a -5 a = 4 b = -1 1 a = 6 b=1 a=6 6 = -1 a=4 6 = 1

Step-by-step explanation:

3 0

3 years ago

How much longer is 18.25 centimeters than 75.4 milimeters

Amanda [17]

Answer:

10.71

Step-by-step explanation:

You first convert 75.4 millimeters to centimeters, and you will get 7.54. Now you subtract 18.25 and 7.54 to get the answer 10.71

4 0

2 years ago

In a statewide lottery, one can buy a ticket for $1. With probability .0000001, one wins a million dollars ($1,000,000), and wit

Dahasolnce [82]

Using the expected value, it is found that the mean of the distribution equals $0.1.

The expected value, which is the mean of the distribution, is given by each outcome multiplied by it's probability.

The probabilities of each outcome are:

.0000001 probability of earning $1,000,000.
.9999999 probability of earning $0.

Thus, the mean is given by:

$E(Y) = 0.0000001(1000000) + 0.9999999(0) = 0.1$

Thus showing that the expected value is $0.1.

A similar problem is given at brainly.com/question/24855677

6 0

2 years ago

HELP pleaseeeeeeeeeeeeeeeee

Yanka [14]

2 rows of geraniums and 4rows of the other one

3 0

2 years ago

Read 2 more answers

You have 100 feet of fencing and decide to make a rectangular garden. What is the largest area enclosed

k0ka [10]

Answer:

625 ft^2

Step-by-step explanation:

Given

$P = 100$ --- perimeter

Required

The largest area

The perimeter is calculated as:

$P = 2 * ( L + W)$

So, we have:

$2 * ( L + W) = 100$

Divide both sides by 2

$L + W = 50$

Make L the subject

$L = 50 - W$

The area is calculated as:

$A= L * W$

Substitute $L = 50 - W$

$A= (50 - W) * W$

Open bracket

$A = 50W - W^2$

Differentiate with respect to W

$A' = 50 -2W$

Set to 0; to get the maximum value of W

$50 - 2W = 0$

Collect like terms

$-2W = -50$

Divide by -2

$W = 25$

So, the maximum area is:

$A = 50W - W^2$

$A = 50 * 25 - 25^2$

$A = 1250 - 625$

$A = 625$

3 0

2 years ago