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2 years ago

If angle 1 and angle 2 are vertical. If the measure angle 1= 6x+11 and the measure angle 2= 10x-9, find the measure angle 1

Mathematics

1 answer:

Paraphin [41]2 years ago

4 0

Hey there!!

We know:- Vertically opposite angles are equal.

Hence,

Angle 1 = Angle 2

... 6x + 11 = 10x - 9

... 20 + 6x = 10x

... 20 = 4x

... x = 20 / 4

... x = 5

Angle 1 = 6x + 11

... 6 ( 5 ) + 11

... 30 + 11

... 41

Hence, the measure of angle 1 is 41 degrees.

Hope my answer helps!

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An animal shelter has 9 puppies. If the puppies are 36% of the total dog and cat population, how many dogs and cats are in the a

Luda [366]

Answer:

Let total number of dog and cat population in animal shelter be x.

As per the statement:

An animal shelter has 9 puppies.

⇒ Total number of puppies = 9

It is also given that if the puppies are 36% of the total dog and cat population.

⇒ $9 = 36\% \text{of}{\text{total number of dogs and Cat}$

$9 = \frac{36}{100} \times x$

By cross multiply we get;

$900 = 36 x$

Divide both sides by 36 we get;

$25 = x$

Therefore, total number of dogs and cat population in animal shelter are 25

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2 years ago

What are the solutions to the following equation? select all that apply. 0= x^2 - x + 5

Dominik [7]

Answer:

I think it is a and f i could be wrong

Step-by-step explanation:

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2 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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2 years ago

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37/2 How do you get the answer?

Andrei [34K]

Answer:

18.5

Step-by-step explanation:

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3 years ago

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melamori03 [73]

Answer:

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I hope this helps!

Step-by-step explanation:

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2 years ago