Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
3/33 can be reduced to 1/11 by dividing by 3 on the top and bottom.
1/11 is not equal to 1/10. Although they have the same numerator or number on top, 1, they don't have the same number in the bottom.
So they are not equivalent.
Hope this helps.
Answer:
Q1:
Share of the daughter (x):
2x + x + x + $1,000 = $9,000
4x = $8,000
x = $2,000
Share of the wife:
= 2($2,000)
= $4,000
Share of the son:
= $2,000 + $1,000
= $3,000
Answer: wife, $4,000; son, $3,000; daughter, $2,000
Q2:
= 1/2x + $1,000
Answer: 1/2x + $1,000: expression for share of the son
Proof (the wife shares $4,000):
Share of wife (x):
x + 1/2x + 1/2x + $1,000 = $9,000
2x = $8,000
x = $4,000
Step-by-step explanation:
hope it helps!
Answer:
k = -3
Step-by-step explanation:
F(x) has a positive slope
g(x) has a negative slope
Let x = -3
The y value goes from 1 to -3
g(x) = k⋅f(x)
-3 = k(1)
-3 = k
