Answer: The criteria to place elements into groups and periods lies in their atomic number
Explanation:
As we know that period is the horizontal rows of elements in the periodic table and groups are vertical column of elements in the periodic table.
In a period we place those elements that have same number of shells and in a group those elements are placed that have different number of shells and the number of shells increases from top to bottom in a periodic table
For example
Sodium having symbol Na, atomic number of sodium is eleven it's electronic configuration is 1s2,2s2,2p6,3s1, next to it in a period is places potassium having symbol,K, it's electronic configuration is 1s2,2s2,2p6,3s2.
Sodium and potassium both r placed in a period not in a group because both of these have same outer most shell, only the number of electron in outer most shell varies.
The answer to this would be 22 mL
Answer:
a) The flame test of Na, at 589nm will show a golden yellow color when the sodium ion is emitted. These is due to the electropositive nature of the alkali metals.
While the flame test for K at 404nm will ignite a violet color when the Potassium ion is emitted. This properties are due to the high electropositive nature of the group1 elements which also indicate their strong reducing agent.
b) The cobalt glass filter act as hindrance during the flame test to seperate or filter the golden yellow color caused as a result of the presence of the sodium, as it makes the violet color to be more visible.
c) These is due to the Oxidizing ability of KClO₄ or KClO₃ compared to the salts of sodium. Also is the low solubility of the two salts and their solubility constant (Ksp) compared to sodium salts.
Explanation:
a) The flame test of Na, at 589nm will show a golden yellow color when the sodium ion is emitted. These is due to the electropositivity nature of the alkali metals.
While the flame test for K at 404nm will ignite a violet color when the Potassium ion is emitted. This properties are due to the high electropositivity nature of the group1 elements which also indicate their strong reducing agent.
b) The cobalt glass filter act as hindrance during the flame test to seperate or filter the golden yellow color caused as a result of the presence of the sodium, as it makes the violet color to be more visible.
c) These is due to the Oxidizing ability of KClO₄ or KClO₃ compared to the salts of sodium. Also is the low solubility of the two salts and their solubility constant (Ksp) compared to sodium salts.
I'm thinking maybe C Hope this helps