What are you needing help with ?????
The answer to your equation is c
I believe that the answer for this question would be option A. 8 HOURS. Based on the given scenario above about a certain radioactive isotope placed near a Geiger counter, the half-life <span>of the isotope 32 hours later would be 8 hours. Hope this is the answer that you are looking for. </span>
Answer:
a, d, f
Explanation:
ΔHrxn = ΔH(CCl4) -ΔH(CH4) = - 106.7 -(-74.8) = - 31.9 kJ/mol