The atmospheric pressure at sea level is greater than on Mount Everest
1 answer:
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Answer:
\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}
Explanation:
Hello,
The suitable differential equation for this case is:
As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:
Of course, .
Now, since the volume of a cone is and the ratio
or
, the volume becomes:
We proceed to its differentiation:
Then, we compute
Finally, at h=2:
Best regards.