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Orlov [11]
3 years ago
15

BRAINLIST ANSWER- You and your friends want to rent a limo on prom night. The limo costs $75 per hour plus a $50 booking fee. Yo

u have $350 to spend. How many hours can you have the limo?(short explanation)

Mathematics
2 answers:
Lelu [443]3 years ago
5 0
First, you would want to subtract the booking fee from the total amount of money you have to spend. 350-50 = 300. 
After paying the booking fee, you would have 300 dollars left to spend. Now, divide the amount of money you have left in all by the cost per hour. 300/75 = 4. 
The answer is B, because you can have the limo for 4 hours.
Hope that helped you.
Zepler [3.9K]3 years ago
5 0
Regardless of how many hours you rent the limo, you'll need to spend $50 to book it. That leaves you with $300. $300 divided by $75 is 4, so you can afford to have the limo for four hours.
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Answer:

a_{n} = a_{1} (\frac{1}{2} )^{n - 1} where a_{1} = 256.

The number of players compete in round 7 will be 4.

Step-by-step explanation:

The number of players in a tennis tournament is reduced by half (50%) after every round. In round 1 there are 256 players, in round 2 there are 128 players, and so on.

So, the number of players is multiplied by \frac{1}{2} gives the number of players in the next round.

Therefore, the explicit function of number of players in nth round is given by  

a_{n} = a_{1} (\frac{1}{2} )^{n - 1} where a_{1} = 256.

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allochka39001 [22]

Answer:

The answer to each question is:

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Step-by-step explanation:

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  • Area of a dodecagon = 6 * apothem * edge

In the exercise, we have the edge (6 cm), but, to find the apothem of a dodecagon, that is the distance between the center of the polygon, and the middle point of each side, you can use the next formula:

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Then,<u> the area of the dodecagon is 403.2 </u>cm^{2}<u> approximately</u>.

B.) As the area obtained is for 12 pieces, when the parents ate 9 pieces, just left 3 pieces, with these values you can make a rule of three.

If:

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In this form, <u>when the cookie has 3 pieces, its area is 100. 8 </u>cm^{2}<u> approximately</u>.

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