Answer: Length: 4, width: 6
Step-by-step explanation:
Let the length be x and width be y
Then x=2y-8 and xy=24
Substitute to get 2y-8 * y = 24, so 2y^2-8y=24 or y^2-4y=12, then solve to get y=6 or y=-2. Since width is positive y=6.
Substitute y=6 into xy=24 to get x=4.
Length: 4, width: 6
Hope that helped,
-sirswagger21
48.7 rounded to one significant figure would be 50
Answer:
The correct option is B. 23%
Step-by-step explanation:
Let the event that patient brushes his teeth at least twice a day is denoted by A
So, P(A) = 0.83
Let the event that patient flosses daily is denoted by B
So, P(B) = 0.47
Now, it is given that 19 percent patients brush at least twice a day and floss daily.
⇒ P(A and B) = 0.19
Now, we need to find conditional probability of occurring event B given A has occurred.
Hence, Nearest required percentage = 23%
Therefore, The correct option is B. 23%
Answer:
28 short race volunteers
76 long race volunteers
Step-by-step explanation:
Let :
Short races = a
Long races = b
LAST YEAR:
7a + 8b = 804 - - - - (1)
THIS YEAR:
11a + 5b = 688 - - - (2)
Multiply (1) by 5 and (2) by 8
35a + 40b = 4020
88a + 40b = 5504
Subtract
-53a = - 1484
a = 1484 / 53
a = 28
Put a = 28 in equation (1)
7(28) + 8b = 804
196 + 8b = 804
8b = 804 - 196
8b = 608
b = 76
28 short race volunteers
76 long race volunteers
