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3 years ago

Solve please i’ll give brainliest

Mathematics

1 answer:

valina [46]3 years ago

6 0

Answer:

3 is 60°, as well as 5 and 7 and the rest are 120°

Step-by-step explanation:

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Solve for x under the assumption that x>0. x-70/x<-3

Reika [66]

x=0,√70,−√70x=0,70,-⁢70x≈0,8.36660026,−8.3666002

6 0

2 years ago

Use the drawing tool(s) to form the correct answer on the provided graph.

AlekseyPX

The solutions to the system of equations are (-2,-6) and (4,6)

<h3>How to determine the system of equations?</h3>

We have:

-2x + y = -2

$y = -\frac12x^2 + 3x + 2$

Next, we plot the graph of both functions.

From the attached graph, the equations intersect at (-2,-6) and (4,6)

Hence, the solutions to the system of equations are (-2,-6) and (4,6)

Read more about system of equations at:

brainly.com/question/21405634

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1 year ago

Factorize this expression completely using (a-b)² formula 3a²- 36a + 108

Novosadov [1.4K]

Answer:

$3a^2 - 36a + 108 = (\sqrt{3}a - 6\sqrt{3} )^2$

Step-by-step explanation:

$3a^2 = (\sqrt{3} a)^2\\108 = 9 \times 4 \times 3= 3^2 \times 2^2 \times 3 = (3\times2 \sqrt{3} )^2 = (6\sqrt{3})^2$

$so, a = \sqrt{3} a \ , \ b = 6\sqrt{3} \\\\(a - b)^2 = a^2 -2ab + b^2\\\\-36a = -2ab\\\\-36a = -2 \times \sqrt{3} a \times 6\sqrt{3}$

Therefore ,

$3a^2 - 36a + 108 = (\sqrt{3}a )^2 - 2(\sqrt{3}a \times 6\sqrt{3} ) + (6\sqrt{3} )^2 = (\sqrt{3}a - 6\sqrt{3} )^2$

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3 years ago

What is the domain of f(x) = √x – 4 over the set of real numbers?

nikklg [1K]

Answer:

(2) x $\geq \\$ 4

Step-by-step explanation:

Given the sqrt(x), x $\geq \\$ zero

So, given sqrt(x -4), x -4 $\geq \\$ 0

Now solve for x

x - 4 $\geq \\$ 0

x $\geq \\$ 4

6 0

2 years ago

Solve for x show all work -2× + 5=4× -7

Anestetic [448]

5=4x+2x-7
5+7=6x
12=6x
12/6=6x/6
2=x

6 0

3 years ago

Read 2 more answers