The average is (time)/(number of problems)=(45/60)/20=(3/4)/20=3/80 hours per problem. In minutes, the answer would be 3/80*60=9/4 minutes per problem.
Answer:
<em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>-</em><em>9</em><em>0</em>
Step-by-step explanation:
hope it helps
Answer: Option C
Step-by-step explanation:
To solve this problem use the properties of the logarithms.
We know that the inverse function of 
is 
.
So when composing the function with its inverse function we have to:
.
Now apply this property on both sides of the equation
the answer is the option C
2ab + a^3 + 5a^2b^2 - 2b^3
= a^3 - 2b^3 + 2ab + 5a^2b^2 (this is the expression in standard form)
Answer:
Can you get a picture please or more detail...
