Best method to solve y=-3x+4 y = 3x-2

Mathematics

1 answer:

Artist 52 [7]3 years ago

7 0

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

( 1 , 1 )

Equation Form:

x = 1 , y = 1

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FOR 50 POINTSSS PLSSS HELPPP IF U HELP ILL SEND 30 MORE POINTSSS

elena-14-01-66 [18.8K]

Answer:

1. t=21+4

2. 25º

Step-by-step explanation:

1. let t=temperature. its 21 now, which is 4 less than it was before, so you add

2. 21+4=25º

hope this helps have a great day/night!!! :))

8 0

2 years ago

For the quadratic y = x^2 -7x +12, when x = -3, what is the y-value?

Tatiana [17]

Answer:

y = 0

Step-by-step explanation:

subsitute x = -3 into y = x^2 - 7x + 12

y = -3^2 - 7 x -3 + 12

= 9 - 21 + 12

= 0

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3 years ago

Read 2 more answers

- 4(6 + 5g) equivalent expressions

Masteriza [31]

Answer:

the awnser is 4g because if you multiply the -4 by 6 and 5 g you get the equation: -24+-20g.. subtract -24 from -20 you will get 4g

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3 years ago

Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha

oksano4ka [1.4K]

I guess the function is $f(x)=9-x^{2/3}$ . Then $f(-27)=0$ and $f(27)=0$ .

The derivative is $f'(x)=-\dfrac23 x^{-1/3}$ , but there is no $c$ such that

$-\dfrac23c^{-1/3}=0$

This doesn't contradict Rolle's theorem because $f'(0)$ does not exists. In other words, $f$ is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")