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Allushta [10]
4 years ago
6

What is 13 in radical fraction form

Mathematics
1 answer:
Tcecarenko [31]4 years ago
5 0
13‾‾‾√≈3.605551275463989
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If the quotient of a number and 6 is added to 1/3, the result is 7/6. Find the number.
lisabon 2012 [21]

The number is 4.

<h3>What is the Quotient?</h3>

A quotient is defined as the outcome of dividing an integer by any divisor that can be said to be a quotient. The dividend contains the divisor a specific number of times.

Let n be the number in question; then, we can write the word problem as an equation like this:

⇒ (n/6) + 1/3 = 7/6

Multiply everything by the least common multiple of all the denominators (6, 3, 6), which is 6.  

⇒ 6(n/6) + 9(1/3) = 6(7/6)

⇒ n + 3 = 7

Subtract 3 from both sides,

⇒ n = 4

Hence, the number is 4.

Learn more about the quotient here:

brainly.com/question/27796160

#SPJ1

3 0
1 year ago
Which expression represents x^2+8x+16? <br>​
salantis [7]

Answer: C

Step-by-step explanation:

To factor a trinomial, you need to multiply 'a' and 'c' and see what two number add to equal 'b' but also multiply to equal the product of 'a' and 'c'.

So, what two numbers multiply to equal 16 but simultaneously add to equal 8?

That is +4 and +4. Instead of writing (x+4)(x+4), you can write (x+4)^2, or answer C.

7 0
3 years ago
Find the vertical asymptote(s) of f of x equals quantity 3 x squared plus 3x plus 6 end quantity over quantity x squared minus 2
Salsk061 [2.6K]

Answer:

a i think give me brainliest. good day.

Step-by-step explanation:

7 0
3 years ago
100 POINTS, WILL MARK BRAINLIEST! If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1).
victus00 [196]

Answer:

The value of h^\prime(1)=5

Step-by-step explanation:

Given that  h(x)=f(f(x))

now to find h(x)=f(f(x)) from the given functions f(x) and f'x

let h(x)=f(f(x))

Then put x=1 in above function we get

h(1)=f(f(1))

=f(3) (from the table f(1)=3 and f(3)=6)

Therefore h(1)=6

Now to find h'(1)

Let

h^{\prime}(x)=f^{\prime}(f^\prime(x)) (since  h(x)=f(f(x)) )

put x=1 in above function we get

h^{\prime}(1)=f^{\prime}(f^\prime(1))

=f^{\prime}(2)    (From the table f^\prime(1)=2 and f^\prime(2)=5)

h^{\prime}(1)=5

Therefore h^{\prime}(1)=5

4 0
3 years ago
Read 2 more answers
I NEEEDDDD HELPPP ASAPPPP!!! it’s urgentttttt
Artist 52 [7]

Answer:

(x + 14)² + (y – 21/2)² = 1

Step-by-step explanation:

The equation of a circle can be written as seen below

(x – h)² + (y – k)² = r²

Where (h,k) is at the center and r = radius

We are given that the radius is 1

We are also given that the center is at (-14,21/2)

So we know that r = 1, h = -14, and k = 21/2

So to find the equation of the circle we simply substitute these values into the equation of a circle

Equation of a circle: (x – h)² + (y – k)² = r²

r = 1, h = -14, and k = 21/2

Substitute values

(x – (-14))² + (y – 21/2)² = 1²

1^2 = 1

The two negative signs before the 14 cancel out and it changes to + 14

The equation of a circle with a center at (-14,21/2) and a radius of 1 is (x + 14)² + (y – 21/2)² = 1

4 0
3 years ago
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