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3 years ago

The slope formula can be used to prove a triangle has

1 answer:

4 0

The slope formula can be used to prove a triangle has
<span>a right angle
and slope formula also prove that lines are parallel
so i conclude option B is correct
hope it helps</span>

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Need help with this continuity problem.

ira [324]

In order to be continuous everywhere, we only need to satisfy continuity at $x=10$ . For that to happen, we need to have

$\displaystyle\lim_{x\to10^-}f(x)=\lim_{x\to10^+}f(x)=f(10)$

By the function's definition, $f(10)=2(10)-2=18$ . Compute the limits:

$\displaystyle\lim_{x\to10^-}f(x)=\lim_{x\to10}2x-2=18$

$\displaystyle\lim_{x\to10^+}f(x)=\lim_{x\to10}-8x+b=-80+b$

So we must have

$18=b-80\implies b=98$

3 0

3 years ago

Survey: On free time 90 students like watching TV, 20 like watching TV but not reading, 80 like reading, 40 do not like watching

Dvinal [7]

Answer:

50 %

Step-by-step explanation:

From the diagram attached,

Percentage of total students that like watching television = [(WnR)/μ]×100......... Equation 1

The number of students that like watching television and reading (WnR) = 70

The total number of students (μ) = 40+20+70+10

The total number of students (μ) = 140

Substitute these values into equation 1

Percentage of total students that like watching television = (70/140)×100

Percentage of total students that like watching television = 1/2(100)

Percentage of total students that like watching television = 50 %

5 0

3 years ago

What does 9.6 divided by 0.08

Mila [183]

Answer:

120

Step-by-step explanation:

9.6÷0.08=120

hope this helped

5 0

3 years ago

Given the function, f(x)=x^2-3 , calculate the average rate of change of the function from x=1 to x=3

viktelen [127]

Rate of change(m) = (f(3) - f(1))/(3-1)

m = (6 - -2)/(3-1)
m = 8/2
m = 4

5 0

4 years ago

Find the derivative of the algebraic functions

jek_recluse [69]

Answer:

10) f'(x) = (x² + 6x - 3)/(x + 3)²

11) g'(x) = 1 - csc²x

Step-by-step explanation:

10. f(x) = x(1 - (4/(x + 3))

Expanding gives;

f(x) = x - (4x/(x + 3))

Differentiating gives;

f'(x) = 1 - 4/(x + 3) + 4x/(x + 3)²

Simplifying this gives;

f'(x) = [(x + 3)² - 4(x + 3) + 4x]/(x + 3)²

f'(x) = (x² + 6x + 9 - 4x - 12 + 4x)/(x + 3)²

f'(x) = (x² + 6x - 3)/(x + 3)²

11. g(x) = x + cot x

Rewriting this gives;

g(x) = x + (1/tan x)

We know that derivative of tan x is sec x while derivative of (1/tan x) is -csc²x

Thus;

g'(x) = 1 - csc²x

This can be written as

Differentiating this gives;

g'(x) = 1 - csc²x

5 0

3 years ago