By looking at how wiggily the bar is lol
A. they have the same acceleration
I hope this helps!
Answer:
56400Joules
Explanation:
The quantity of heat required is expressed as;
Q = mL
m is the mass = 25g = 0.025kg
L is the latent heat of vaporization for steam = 2.256×10^6J/kg
Substitute into the formula as shown;
Q = 0.025×2.256×10^6
Q = 56400Joules
Hence the quantity of hear required is 56400Joules