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nadezda [96]
3 years ago
7

Pressure and volume changes at a constant temperature can be calculated using

Physics
1 answer:
V125BC [204]3 years ago
3 0

Answer:

Option A, Boyle's law

Explanation:

The complete question is

Pressure and volume changes at a constant temperature can be calculated using

a. Boyle's law. c. Kelvin's law.

b. Charles's law. d. Dalton's law.

Solution

In Boyle’s law, the gas is assumed to be ideal gas and at constant  temperature. With these two conditions fixed, Boyle’s established that volume of gas varies inversely with the absolute pressure.  

The basic mathematical representation of this phenomenon is as follows -  

P \alpha \frac{1}{V}

OR

P = \frac{k}{V} \\PV = k

Where P is the pressure of ideal gas, V is the volume and k is the constant of proportionality.

Hence, option A is correct

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A 250 kg flatcar 25 m long is moving with a speed of 3.0 m/s along horizontal frictionless rails. A 61 kg worker starts walking
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Answer:

x=31.09m

Explanation:

p1=p2

The momentum of flatcar and the momentum of the worker so

The velocity of the worker is:

m_{f}*v_{f}=m_{w}*v_{w}\\\\v_{f}=\frac{m_{f}*v_{f}}{m_{w}}\\v_{f}=\frac{61kg*3.0\frac{m}{s}}{250kg}\\v_{f}=0.732\frac{m}{s}

The total motion has a total velocity and is

Vt=v_{w}+v_{f}\\Vt=0.732\frac{m}{s}+3.0\frac{m}{s}\\Vt=3.732\frac{m}{s}

The time the worker take walking is

t=\frac{x}{v_{w}}\\t=\frac{25m}{3\frac{m}{s}}=8.33s

Now the total time and the total velocity determinate the motion of tha flatcar how far has moved

x=t*Vt\\x=8.33s*3.732\frac{m}{s} \\x=31.09m

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3 years ago
What was the name of the first living being to be put into orbit?.
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Which lens combination is used to treat presbyopia ~ ​
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Contrast the force of gravity between these pairs of objects a 1 kg mass and a 2 kg mass that are 1 m apart and two 2 kg masses
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Solution

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F=G\times \frac{1\times 2}{1^2}

here G is gravitational constant

G=6.674\times10^{-11}Nm^2kg^{-2}

therefore,

F=6.674\times10^{-11}Nm^2kg^{-2}\times 2

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similarly Force between pair of objects of masses 2kg each that are 1m apart is given as

F'=G\times \frac{2\times 2}{1^2}

F'=6.674\times10^{-11}Nm^2kg^{-2}\times 4

F'=2\times 13.348\times10^{-11}Nm^2kg^{-2}

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When a substance goes directly from a gaseous state to a solid state as dry ice does
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