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leonid [27]
3 years ago
14

3. A 20 kg lawnmower is pushed by its handle, which makes a 40 degree angle with the horizontal. What

Physics
1 answer:
Mkey [24]3 years ago
5 0

<u>13788 J is required to finish the work.</u>

Explanation:

Given that,  

Mass of lawnmower is 20 kg  

Force = 30 N

\text { Angle }(\theta)=40^{\circ}

Displacement ( distance moved )= 20m

The force of 30N is applied along the direction of motion and was applied for the whole 20 m.

The formula of work done for one pass is

\text { Work done }=\text { force } \times \text { displacement } \times \cos \theta

Substituting the given data into the formula,

W=30 \times 20 \times \cos 40^{\circ}

\mathrm{W}=600 \times \cos 40^{\circ}

\mathrm{W}=600 \times 0.766

W = 459.6 J

Work done for one pass = 459.6J

Now, work done for 30 passes is calculated by multiplying the work done for one pass into 30.

\text { Then the work done for } 30 \text { passes is } 459.61 \times 30=13788 \mathrm{J}

Work is done by the person pushing the mower to finish the work is <u>13788 J</u>.

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Hope this helped!

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