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leva [86]
3 years ago
10

The ratio of pencils to pens in the drawer is 8:14. If there are actually twice as many pencils as in the ratio, how many pencil

s and pens are there in the drawer?
A. 8 pens, 14 pencils

B. 8 pencils, 14 pens

C. 16 pens, 28 pencils

D. 16 pencils, 28 pens
Mathematics
1 answer:
dusya [7]3 years ago
6 0

Yo sup??

let the number of pencils and pens be 8x and 14x

x=2

therefore the number of pens and pencils are

16 pencils and 28 pens

Hope this helps

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Carrie is buying bulk candy for a high school fundraiser. She buys 1000 candy bars for $350. What is the unit cost per candy bar
liubo4ka [24]
1000 candy bars ... $350
1 candy bar ... $x = ?

If you would like to know what is the unit cost per candy bar, you can calculate this using the following steps:

1000 * x = 350 * 1
1000 * x = 350    /1000
x = 350 / 1000
x = $0.35

Result: She can buy 1 candy bar for $0.35, so the correct result would be B) $.35.
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A boat traveled 128 kilometers in
AlekseyPX

Answer:

The Distance cover by boat in 2 hours and 15 minutes is 72 km  

Step-by-step explanation:

Given as :

The Distance cover by boat = 128 kilometer

The time taken is 4 hours

As , Distance = Speed ×Time

So , Speed = \frac{Diastance}{Time}

Or, Speed = \frac{128 km}{4 hours}

∴   Speed = 32 km per hour

Now, again The boat travel 2 hours and 15 minutes further with speed 32 kmph

So, Time2 = 2 + \frac{15}{60}

Or,  Time2 = 2 + \frac{1}{4}

I.e Time2 = \frac{9}{4}  hours

Again , Distance = Speed ×Time

So ,    Distance = 32kmph × \frac{9}{4}  hours

I.e       Distance  = (\frac{32\times 9}{4}) = 72 kilometer

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dem82 [27]

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Step-by-step explanation:

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There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

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Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

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