Answer: 0.0793
Step-by-step explanation:
Let the IQ of the educated adults be X then;
Assume X follows a normal distribution with mean 118 and standard deviation of 20.
This is a sampling question with sample size, n =200
To find the probability that the sample mean IQ is greater than 120:
P(X > 120) = 1 - P(X < 120)
Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n
Where; X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size
Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)
= 1 - P(Z< 1.41)
The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207
Thus; P(X< 120) = 1 - 0.9207
= 0.0793
Answer:
never did this with big numbers but i will try lol! okay so the word "is" means the number after that with be of the top. And the word "of" (and the nummber after that) will always be on the bottom. so remember is/of
Step-by-step explanation:
5% so you will have 5/100
IS $70,000 (70,000 will be on the top of your fraction)
and you know what ill just give you the dang answer LOL!
is your answer 1,400,000? if so thats the answer
m^2 -11m -60 = 0
m^2 -11m =60
(m^2 -11m + 121/4) = 361/4
(m - 11/2)^2 = 361/4
m - 11/2 = + or - 19/2
m = 11/2 + 19/2, 11/2 - 19/2
m = 15, -4
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m^2 -11m -60
(11 +- Square root (121 +240))/2
11/2 +- 19/2
m= 15, -4
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m^2 -11m -60
(m - 15) (m + 4)
m = 15, -4
Answer:
40/8 or 5
Step-by-step explanation:
