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ikadub [295]
3 years ago
10

Hannah walks 2 miles each day to work then she walks two miles home how many yards does she walk to and from work each day

Mathematics
1 answer:
Damm [24]3 years ago
7 0
Hey there! Every mile is 1760 yards, so multiply that by 4
1760 x 4 = 7040, so she walks 7040 yards.
Hope this helped!
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What is the 72nd term of -27, -11, 5
FinnZ [79.3K]

Answer:

1109

Step-by-step explanation:

The first term is -27, and the common difference is 16.

The nth term is:

a = a₁ + d (n − 1)

a = -27 + 16 (n − 1)

a = -27 + 16n − 16

a = 16n − 43

The 72nd term is:

a = 16(72) − 43

a = 1109

5 0
3 years ago
Please give me the correct answer ​
Yuri [45]

Answer: 36/9

Step-by-step explanation:

8 0
2 years ago
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
3 years ago
Melissa got two puppies, Ben and Sadie.
MA_775_DIABLO [31]

Answer:

x = 4y - 20

Step-by-step explanation:

x = Sadie's weight

y = Ben's weight

x = 4(y - 5)

x = 4y - 20

7 0
3 years ago
A train traveled 63.75 miles at a rate of 85 miles per hour. Which equation can be used to find h, the number of hours it took t
sashaice [31]

Answer:  63.75 = 85h

Solving gives 0.75 hours.

Step-by-step explanation:

we now that speed = distance / time

therefore time will be Distance / speed

Given that distance = 63.75miles

Speed= 6=85miles per hour

Time(h) = 63.75miles/ 85.---- equation 1

But from the options given, the equation that can also  be used to find number of hours is

63.75 = 85h

such that making h subject of formula  still give us

h= 63.75/85  as in equation 1 above

solving gives that Time ( h) = 0.75 hours .

8 0
2 years ago
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