Answer:
0.0045248 ;
0.1312218 ;
0.0001809 ;
0.1659729
Step-by-step explanation:
Number of Kings in deck = 4
Total number of cards in deck = 52
Picking without replacement :
A = King on first draw :
P(A) = 4 / 52
A = King on 2nd draw :
P(B) = 3 / 51
A = King on 3rd draw :
P(C) = 2 / 50
1.) P(A n B) = P(A) * P(B)
P(A n B) = 4/52 * 3/51 = 12 / 2652 = 0.0045248
2.) P(A u B) = P(A) + P(B) - P(AnB)
P(AuB) = 4/52 + 3/51 - 0.0045248 = 0.1312218
3.) P(A ∩ B ∩ C) = P(A) * P(B) * P(C)
P(A ∩ B ∩ C) = 4/52 * 3/51 * 2/50 = 0.0001809
4.) P(A U B U C) =
P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) - P(AnBnC)
P(AnC) = P(A) * P(C) = 4/52 * 2/50 = 0.0030769
P(BnC) = P(B) * P(C) = 3/51 * 2/50 = 0.0023529
4/52 + 3/51 + 2/50 - 0.0045248 - 0.0030769 - 0.0023529 + 0.0001809 = 0.1659729
The graph is **increasing on the interval (-2, 1)**because the graph has a positive slope from x=-2 to x=1. It’s **decreasing at the intervals (-infinity, -2) and (1, infinity)**because the graph has a negative slope between the x values -infinity to -2 and is also decreasing between the x values of 1 and infinity.
Answer:
One- half
Step-by-step explanation:
Since the density is uniform
Mass of the sphere = [(4/3) π r^3] d
where d is the uniform density.
Mass of the sphere = [(4/3) π d] r^3 = k r^3
where k = [(4/3) π d] is a constant
Weight = mg = G m M / r^2 = G m [k r^3] /r^2 = G m k r
Using Gauss’ law for gravitation,
Half way to the center of a planet the weight is only due to the inner sphere and the outer sphere does not contribute to his weight,
Inside his weight is mg’ = (G m k r) /2 = mg/2
Answer is one-half.
8.992254284692088 is the radius I believe
