I saw the graph.
The circle was divided into 4 quadrants. Each having an angle of 90°. 30° was given and it originated from the positive y-axis.
Using the standard position, the angle of fire in both degrees and radians is:
90° - 30° = 60°
1pi = 180°
60° = 180°/3 so pi over 3.
the answer is: 60° ; pi over 3
The answer is no, I think
Answer:
<CDG = 118 degrees
Step-by-step explanation:
Alternate interior angles are congruent.
The answer is $300 because you have to multiply 25x12. 10x25=250 and 2x25=50. 250+50=300.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The differential equation that fits the physical description is ![\frac{d (v(t))}{dt} = z [v(t)]^2](https://tex.z-dn.net/?f=%5Cfrac%7Bd%20%28v%28t%29%29%7D%7Bdt%7D%20%3D%20z%20%5Bv%28t%29%5D%5E2)
Step-by-step explanation:
From the question we are told that
The acceleration due to air resistance of a particle moving along a straight line at time t is proportional to the second power of its velocity v, this can be mathematically represented as
![a(t) \ \ \alpha \ \ \ [v(t)]^2](https://tex.z-dn.net/?f=a%28t%29%20%5C%20%20%5C%20%20%5Calpha%20%20%5C%20%5C%20%5C%20%5Bv%28t%29%5D%5E2)
Where
is the acceleration at time t
and
is the velocity at time t
So
=> ![a(t)= z [v(t)]^2](https://tex.z-dn.net/?f=a%28t%29%3D%20z%20%5Bv%28t%29%5D%5E2)
Where z is a constant
Generally acceleration is mathematically represented as
![a(t) = \frac{d (v(t))}{dt}](https://tex.z-dn.net/?f=a%28t%29%20%3D%20%20%5Cfrac%7Bd%20%28v%28t%29%29%7D%7Bdt%7D)
So
![\frac{d (v(t))}{dt} = z [v(t)]^2](https://tex.z-dn.net/?f=%5Cfrac%7Bd%20%28v%28t%29%29%7D%7Bdt%7D%20%3D%20%20z%20%5Bv%28t%29%5D%5E2)