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lilavasa [31]
3 years ago
7

What times what equals 104

Mathematics
1 answer:
pochemuha3 years ago
7 0
1×104=104
2×52=104
4×26=104
8×13=104
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Identify each number as rational or irrational.
emmasim [6.3K]

Answer:

1. Rational

2. Irrational

3. Irrational

4. Rational

5. Irrational

Step-by-step explanation:

Rational numbers are numbers you can identify as the ratio of two integers. Which means they don't go on forever. 1 and 4 are both rational numbers while 2, 3, and 5 are irrational.

4 0
2 years ago
U(x)=x-1<br> W(x)=2x^2-2<br><br> (U.w)(1)=<br> (W•u)(1)=
Kryger [21]

Answer: I really don’t know lol

Step-by-step explanation:

8 0
3 years ago
The area of an ​20 -cm-wide rectangle is 440 cm. What is its​ length?
Nataly [62]

Answer:

22cm

Step-by-step explanation:

440÷20

8 0
3 years ago
Alice and Bob play a game involving a circle whose circumference is divided by 12 equally-spaced points. The points are numbered
inn [45]

Answer:

Step-by-step explanation:

2005 AMC 8 Problems/Problem 20

Problem

Alice and Bob play a game involving a circle whose circumference is divided by 12 equally-spaced points. The points are numbered clockwise, from 1 to 12. Both start on point 12. Alice moves clockwise and Bob, counterclockwise. In a turn of the game, Alice moves 5 points clockwise and Bob moves 9 points counterclockwise. The game ends when they stop on the same point. How many turns will this take?

$\textbf{(A)}\ 6\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 14\qquad\textbf{(E)}\ 24$

Solution

Alice moves $5k$ steps and Bob moves $9k$ steps, where $k$ is the turn they are on. Alice and Bob coincide when the number of steps they move collectively, $14k$, is a multiple of $12$. Since this number must be a multiple of $12$, as stated in the previous sentence, $14$ has a factor $2$, $k$ must have a factor of $6$. The smallest number of turns that is a multiple of $6$ is $\boxed{\textbf{(A)}\ 6}$.

See Also

2005 AMC 8 (Problems • Answer Key • Resources)

Preceded by

Problem 19 Followed by

Problem 21

1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25

All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

5 0
2 years ago
Can you help? photo is included<br><br><br><br><br><br><br>​
laiz [17]

Answer:

Step-by-step explanation:

f(x)=-4x+2

g(x)=x²+1

(gof)(x)=g(f(x))=g(-4x+2)=(-4x+2)²+2=16x²-16x+4+2=16x²-16x+6

(gof)(3)=16(3)²-16(3)+6=144-48+6=150-48=102

3 0
3 years ago
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