"A Buffer overflow" vulnerability exploit resulted from the attacker's actions.
Whenever a software or an application writes too much data into a buffer, causing neighboring storage regions to have been corrupted as a consequence, this could be determined as Buffer overflow.
⇒ There are two kinds of Buffer overflow attacks such as:
- <u>Stack-based</u> - It will become more popular to use such memory, as well as that's only available during implementation of any code.
- <u>Heap-based</u> - Those attacks seem to be more difficult to execute because they entail overflowing overall storage capacity allotted for a program further than the space needed for something like the program's present activities.
Thus we can say that the correct answer is a Buffer overflow.
Learn more about Buffer overflow here:
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Answer:
When it's too hot or too cold.
Explanation:
When a bulb of the wrong size or voltage is used in the fixture, the ballast often overheats, causing the light to shut off. The bulbs and the fixture must also match in frequency, or the ballast becomes overworked and overheated.
L is a decidable language because the Turing machine accepts it.
L is a recognizable language if TM M recognizes it.
<h3>How do you know if a language is decidable?</h3>
A language is said to be decidable only when there seems to exists a Turing machine that is said to accepts it,
Here, it tends to halts on all inputs, and then it answers "Yes" on words that is seen in the language and says "No" on words that are not found in the language. The same scenario applies to recognizable language.
So, L is a decidable language because the Turing machine accepts it.
L is a recognizable language if TM M recognizes it.
Learn more about programming language from
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The issue arises because the string you are trying to print is not a string, rather a float value. Item1, item2 and item3 are strong values (if you type some alphabets in it and not just numbers), but itemonecost, itemtwocost, and itemthreecost are explicitly type casted to float. In line 22, 23, and 24 you’re trying to print a float, by adding it with the string. One cannot add numbers to string. Rather you can type cast the itemcost to string while printing.
Add str(itemonecost) instead of itemonecost in print statement. Do this for other float variables too.
However do note that there are multiple ways to correct this issue, and I’ve just pointed one out.
