Answer:
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Step-by-step explanation:
We formulate null and alternate hypotheses are
H0 : u1 < u2 against Ha: u1 ≥ u 2
Where u1 is the group tested after they were awake for 24 hours.
The Significance level alpha is chosen to be ∝ = 0.05
The critical region t ≥ t (0.05, 13) = 1.77
Degrees of freedom is calculated df = υ= n1+n2- 2= 5+10-2= 13
Here the difference between the sample means is x`1- x`2= 35-24= 11
The pooled estimate for the common variance σ² is
Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]
= 1/13 [ 120²+360²]
Sp = 105.25
The test statistic is
t = (x`1- x` ) /. Sp √1/n1 + 1/n2
t= 11/ 105.25 √1/5+ 1/10
t= 11/57.65
t= 0.1908
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Answer:
13.89
Step-by-step explanation:
A^2+B^2=C^2
7^2+12^2=C^2
193 = C^2
193 square root = 13.89
Answer:
Step-by-step explanation:
y ∝ x^2
Introducing the proportionality constant, we have
y = kx^2
Given : y= 18 when x = 3
substitute the given values in order to get the constant
i.e 18 = k x 3^2
18 = 9k
k = 2
therefore the formula connecting x and y
⇒ y = 2x^2
To find y if x is 4, just substitute x = 4 into the formula connecting x and y
i.e y = 2 x 4^2
= 2 x 16
= 32
Answer:
1) c=.07h+15.25 is the answer.
