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3 years ago

The pic is above ^ please help! thank youu!!

Mathematics

2 answers:

AlekseyPX3 years ago

7 0

Answer:B 108
please correct me if im wrong im not sure if i did the math correct
if its right than ur very welcome

Maurinko [17]3 years ago

6 0

C. 144

I think I just explained all of it.

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How to find the exact value of each trigonometric function without a calculator?

Goryan [66]

Remember them is the best way to go.
draw the exact value triangles if you're unsure, but importantly, you just need to memorise these exact values.

5 0

3 years ago

Here is a diagram of a black circle inside a white square and a diagram of a small grey square inside a white square.

nika2105 [10]

The ratio of the area of the black circle to the area of the white square to the area of the gray square is π : 4 : 2

<h3>How to determine the ratio of the areas?</h3>

The side length AB is given as:

AB = 8x

The area of the white square is calculated as

White = (AB)²

This gives

White = (8x)²

Evaluate

White = 64x²

The side length AB represents the diameter of the black circle.

So, the radius is:

r =AB/2

This gives

r = 8x/2 = 4x

The area is then calculated as:

Circle = πr²

This gives

Circle = π(4x)²

Evaluate

Circle = 16πx²

Next, calculate AW and AZ using:

AZ = AW = AB/2

Evaluate

AZ = AW = 8x/2 = 4x

Calculate WZ using the following Pythagoras theorem

WZ² = AW² + AZ²

This gives

WZ² = (4x)² + (4x)²

Evaluate

WZ² = 2(4x)²

Take the square root of both sides

WZ = 4x√2

The area of the gray square is:

Gray = WZ²

This gives

Gray = 2(4x)²

Evaluate

Gray = 32x²

At this point, the areas are:

White = 64x²
Circle = 16πx²
Gray = 32x²

The ratio is then represented as:

Ratio = Circle : White : Gray

This gives

Ratio = 16πx² : 64x² : 32x²

Divide through by 16x²

Ratio = π : 4 : 2

Hence, the ratio of the area of the black circle to the area of the white square to the area of the gray square is π : 4 : 2

Read more about areas at:

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1 year ago

Fill in the chart on paper than list the coefficient of x^2 term.

slamgirl [31]

I am assuming you're doing a Punnet square, so you multiply each one. So on the top left box, it is -45x^2, the top right is 9x, bottom left is 35x, and bottom right is -7.

8 0

3 years ago

Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.

sdas [7]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation is given below.

$PV = nRT$

The equation can be written as

$\rm PV = \dfrac{m}{M} \ RT\\\\\\MPV = mRT$

Where M is the molar mass, P is the pressure, V is the volume, R is the universal gas constant, T is the temperature, and m is the mass of the gas.

Then the molar mass of a 0.622-gram sample of gas has a volume of 2.4 L at 287 K and 0.850 atm.

V = 2.4 L = 0.0024

P = 0.85 atm = 86126.25 Pa

T = 287 K

m = 0.622

R = 8.314

Then we have

$\begin{aligned} \rm M \times 86126.25 \times 0.0024&= 0.622 \times 8.314 \times 287\\\\\rm M &= 7.18 \end{aligned}$

Then the molar mass of the gas is 7.18.

More about the ideal gas equation link is given below.

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6 0

1 year ago

PERCENT PROPORTION

postnew [5]

Answer:

i dont know im so sorry i really need points someone took all mine by reporting them and i need to ask a question for an assignment due in 10 min and i need help again im so sorry

Step-by-step explanation:

3 0

3 years ago