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andreyandreev [35.5K]
3 years ago
15

The pic is above ^ please help! thank youu!!

Mathematics
2 answers:
AlekseyPX3 years ago
7 0
Answer:B 108
please correct me if im wrong im not sure if i did the math correct
if its right than ur very welcome
Maurinko [17]3 years ago
6 0
C. 144

I think I just explained all of it.

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3 years ago a father was 3 times as old as his son, in five years time he will be twice as old as his son, what will be the sum
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Answer: 46 years

Step-by-step explanation:

Let the father's age be x and the son's age be y, then 3 years ago:

Father = x - 3

son     = y - 3

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x - 3 = 3 ( y - 3 )

x - 3 = 3y - 9

x     = 3y - 9 + 3

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In five years time

father = x + 5

son = y + 5

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x + 5 = 2 ( y + 5 )

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x       = 2y + 10 - 5

x       = 2y + 5 ........................ equation 2

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3y = 2y + 5 + 6

subtract 2y from both sides

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y = 11

substitute y = 11 into equation 1 to find the value of x

x = 3y - 6

x = 3(11) - 6

x = 33 - 6

x = 27

This means that the father is presently 27 years and the son is presently 11 years.

In four years time

father = 27 + 4 = 31

son = 11 + 4      = 15

sum of their ages in four years time will be

31 + 15 = 46 years

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3 years ago
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If a 40-m rope is cut into two pieces in the ratio 3:5 how long is each piece
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3:5.....added = 8

3/8(40) = 120/8 = 15 m <== one piece
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