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ikadub [295]
3 years ago
13

What is 9 divided by 1,215?

Mathematics
1 answer:
Otrada [13]3 years ago
7 0

Answer:It equals 135

Step-by-step explanation:

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Could anyone help with this, im terrible at geometry haha
bekas [8.4K]

Answer:

10.90⁰

11.126⁰

12.54⁰

13.180⁰

Step-by-step explanation:

CDE is 180⁰ because it is a straight line

3 0
2 years ago
Read 2 more answers
What is 50,779 divided by 590? Attach work pretty plz
nignag [31]
50,779/590 is 90.7125 but rounded to 90.71
6 0
3 years ago
Solve for x. show your work.​
vova2212 [387]

Hello!

\large\boxed{x = 8}

The two angles pictured are corresponding angles, so they are congruent.

Therefore:

17x - 4 = 12 + 15x

Isolate for x by subtracting 15x from both sides:

2x - 4 = 12

Add 4 to both sides:

2x = 16

Divide both sides by 2:

x = 8.

5 0
3 years ago
Read 2 more answers
A company compiles data on a variety of issues in education. In 2004 the company reported that the national college​ freshman-to
nasty-shy [4]

Answer:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

Step-by-step explanation:

For this case we know that we have a sample of n = 500 students and we have a percentage of expected return for their sophomore years given 66% and on fraction would be 0.66 and we are interested on the distribution for the population proportion p.

We want to know if we can apply the normal approximation, so we need to check 3 conditions:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

And we can use the empirical rule to describe the distribution of percentages.

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

8 0
3 years ago
Consider the expression: (x + y + 3) × (y + 1).
Vladimir79 [104]

Answer:

1 and 2) After multiplying (x+y+3)(y+1) we have

  • xy+x+y^2+4y+3

Which is an equivalent expression after applying the distributive property.

As we can see we have an one of the variables squared,  so we obtain an Parabolic Cillinder

4 0
3 years ago
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