All categories

2 years ago

Which is greater one fourth or two thirds

Mathematics

2 answers:

Zigmanuir [339]2 years ago

5 0

Answer:

2/3

Step-by-step explanation:

If you look at the 2 fractions 1/4 and 2/3, you can visualize 1/4 as 0.25. You can also visualize 2/3 as 0.(66). 0.(66) is obviously bigger, so 2/3 is the greater fraction.

ra1l [238]2 years ago

3 0

Answer:

2/3

Step-by-step explanation:

You might be interested in

The original cost of a cell phone is x dollars. The phone is on sale for 35% off. What would be the simplified expression for th

Nonamiya [84]

X · 0.65 = y or x-(x · 0.35)= y y=sales cost

5 0

3 years ago

Read 2 more answers

Which conic section does the equation below describe? x+2^2=4y-3

Dmitry [639]

Answer: Circle

Step-by-step explanation:

6 0

2 years ago

A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum

Ivan

Answer:

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solution

$y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solving the differential equation

$\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}$

Initial conditions:

$y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

$y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48$

The rumor reaches 80% at 8.48 days.

8 0

2 years ago

Find all zeros of function and write the polynomial as a product of linear factorsX^3-x^2+9x-9

mart [117]

Answer:

$\large\boxed{x=1\ \vee\ x=-3i\ \vee\ x=3i}$

Step-by-step explanation:

$\text{The zeros:}\\\\x^3-x^2+9x-9=0\\\\x^2(x-1)+9(x-1)=0\\\\(x-1)(x^2+9)=0\iff x-1=0\ \vee\ x^2+9=0\\\\x-1=0\qquad\text{add 1 to both sides}\\x-1+1=0+1\\\boxed{x=1}\\\\x^2+9=0\qquad\text{subtract 9 from both sides}\\x^2=-9$

8 0

3 years ago

Write the next three terms of the arithmetic sequence.<br> First term: 2<br> Common difference: 13

IRINA_888 [86]

15, 28, 41.

add the common difference to each consecutive term to find the next term in the sequence.

2+ 13= 15
15+ 13= 28
28+ 13= 41

4 0

2 years ago