Answer:
See below
Explanation:
First, we need to get the predetermined rate
Predetermined rate = Cost of manufacturing overhead / Cost driver
= $1,800,000/60,000
= $30
We will now calculate the application.
Actual labor hours × rate
= 61,500 × $30
= $1,845,000
We will now compare actual with overhead cost
= Applied Overhead cost - Actual manufacturing overhead
= $1,845,000 - $1,810,000
= $35,000
The above is an over application of overhead cost because the cost applied exceed the actual cost.
Answer:
Neighbourhood centre
Explanation:
A neighbourhood centre is a place where local local residents have access to a wide range of services. People gather for group activities, social support, public information and so on.
Phil stopped at a shopping center. He parked in front of the dry cleaner, where he could pick up his suit. He did not have to move his car because next door was a gift shop where he could pick up a gift for his niece. Conveniently enough, next door to that store was a supermarket, where he purchased essentials like milk and cornflake cereal.
Phil is at a neighbourhood centre where wide variety of services are provided locally.
Answer:
The chosen option (considering enrollment costs and opportunity cost) is:
b) College course.
Explanation:
a) Data and Calculations:
Costs/Benefits
College Course Community Course
Cost $2,600 $1,390
Opportunity costs -2,080 2,080
Net costs $520 $3,470
Distance to course 0.40 miles 16 miles
(walking distance) (driving distance)
Timing of course Weekday Weekend
Number of meetings 16 8
b) With the College course option, you will earn $2,080 ($260 * 8) weekdays to offset part of the enrollment cost. With the Community course option, $2,080 will be lost in opportunity cost, thereby increasing the total costs incurred. These costs are apart from the driving costs associated with traveling 16 miles to the Community Course at the local library.
Answer:
Total value of the investment= $57,320.73
Explanation:
<u>First, we need to calculate the future value of the first part of the investment. We will calculate the future value for the monthly deposit for five years and then the lump sum for another five years.</u>
FV= {A*[(1+i)^n-1]}/i
A= monthly deposit
i= 0.04/12= 0.003333
n= 5*12= 60 months
FV= {322*[(1.003333^60) - 1]} / 0.003333
FV= $21,348.05
<u>For the lump sum:</u>
FV= PV*(1+i)^n
n= 12*5= 60
i= 0.05/12= 0.004167
FV= 21,348.05*(1.004167^60)
FV= $27,397.75
<u>Now, the future value of the second part of the investment:</u>
<u></u>
n= 60
i= 0.0041667
A= 440
FV= {440*[(1.004167^60) - 1]} / 0.004167
FV= $29,922.98
Total value of the investment= 27,397.75 + 29,922.98
Total value of the investment= $57,320.73
Answer:
correct option is a $0
Explanation:
given data
Acquisition value = $52,000,000
Fair value assets = $48,000,000
to find out
What is the annual amortization of goodwill for this acquisition
solution
we know that annual amortization of goodwill on a straight line basis over 40 years before 2001
and FASB also issue statement about that it does not allow automatic amortization of goodwill
so it will be zero here as goodwill is not amortized here
so correct option is correct option is a $0
