Answer:
(c).
Step-by-step explanation:
h(t) = - 16 t² + 80 t
Coordinates of the vertex are:
<em>t</em> = -
=
= <em>2.5 sec. </em>
<em>h</em> = - 16(2.5)² + 80(2.5) = - 100 + 200 = <em>100 ft</em>.
2a because with 18a and 20ab they both have "a" in common and they are even thus multiples of 2 leaving you with 2a(9,10b)
Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
A six digit number that fits this criteria is 588588, for this number divided by 11 is a whole number, 53508. If you don't need to use both numbers, 555555 and 888888 also work as answers.