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erik [133]
3 years ago
9

Find three consecutive odd integers such that

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

17, 19, 21

Step-by-step explanation:

x = first number

x+2 = second number

x+4 = third number

4x + 3(x+2) + 2(x+4) = 167

simplify:

4x + 3x + 6 + 2x + 8 = 167

combine like terms:

9x + 14 = 167

subtract 14 from each side of the equation:

9x = 153

divide both sides by 9:

x = 17

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Max has a science test on Thursday. On Monday he studied 2/9 of the material. On Tuesday he studied 1/4 of the remaining materia
wolverine [178]

Answer:

The answer to your question is:

Fraction he has review =  17/36

Fraction he have to study = 19/36

Step-by-step explanation:

Data

Monday studied = 2/9

Tuesday = 1/4

Fraction he has review = ?

Fraction he has left = ?

Process

As the denominator is 9, consider the whole is 9.

Then:    Fraction left on Monday = 9/9 - 2/9

                                                      = 7 / 9

Fraction left on Tuesday = 7/9 - 1/4

                                         = (28 - 9) / 36

                                        = 19 / 36

Fraction he has review =  17/36

Fraction he have to study = 19/36

3 0
3 years ago
Rearrange the equation to isolate A.<br> H=K+log(A/C)
Xelga [282]

Answer:

A=C(10)^{H-K}

Step-by-step explanation:

The given equation is

H=K+\log(\frac{A}{C}

Subtract K to both sides of the equation

H-K=\log(\frac{A}{C}

Now, use the property, x=\log y\Rightarrow y=10^x

10^{H-K}=(\frac{A}{C}

Multiply both sides by C to isolate A

A=C(10)^{H-K}

The value of A is

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3 years ago
Read 2 more answers
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evablogger [386]
400+110+13
All u do is take the first number and add how many numbers behind in 0
exp: 3 hundred 13 tens 16 ones
Answer: 300+ 130+16
3 0
3 years ago
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