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olasank [31]
3 years ago
11

What is the seventh term 81,27,9,...

Mathematics
1 answer:
igomit [66]3 years ago
3 0
The answer would be 0.111111111111. It is odd, but you must divide each term by 3.
You might be interested in
Find the value of S for an infinite geometric series with r =1/6 and a1= 10.
fiasKO [112]
Kind of the whole point of an infinite geometric series is that you can't find the sum. If it is infinite, then the sum is infinite. 
3 0
3 years ago
2. Koil and Karry want to order the figures from greatest to least
Tom [10]

Given:

Figures A, B and C.

To find:

The order of the figures and volume of each figure.

Solution:

<u>Figure A:</u>

Length = 10, Width = 2 and Height = 2

Volume of A = length × width × height

                     = 10 × 2 × 2

Volume of A = 40 cubic units

<u>Figure B:</u>

Length = 3, Width = 3 and Height = 1

Volume of B = length × width × height

                     = 3 × 3 × 1

Volume of B = 9 cubic units

<u>Figure C:</u>

Length = 6, Width = 3 and Height = 3

Volume of C = length × width × height

                     = 6 × 3 × 3

Volume of C = 54 cubic units

Order from greatest to least:

54 < 40 < 9

C < A < B

Hence Kurry said the correct answer.

7 0
3 years ago
The supervisor at the second job says, “I’ll give you a penny today and double your pay every day for 30 days if you’ll work for
Murrr4er [49]
I think it would be a 60 penny's and the interest is 2 x 30
8 0
3 years ago
Read 2 more answers
Find the distance between the points given. (-3, 2) and (9, -3) A √37 B √61 C 13​
Kitty [74]

Answer:

\huge{ \fbox{ \sf{13 \: units}}}

Option C is correct.

Step-by-step explanation:

\star{ \sf{ \: Let \: the \: points \: be \: a \: and \: b}}

\star{ \sf{ \: let \: A(-3, 2) \: be \: (x1 \:, y1) \:  and  \: B(9, -3) \: be \: (x2 \:, y2) }}

\underline{ \sf{Finding \: the \: distance \: between \: the \: given \: points}} :

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{  \sqrt{ {(9 - ( - 3))}^{2} +  {( - 3 - 2)}^{2}  } }}

\mapsto{ \sf{ \sqrt{ {(9 + 3)}^{2}  +  {( - 3 - 2)}^{2} }}}

\mapsto{ \sf{ \sqrt{ {(12)}^{2}  +  {( - 5)}^{2} } }}

\mapsto{ \sf{ \sqrt{144 + 25}}}

\mapsto{ \sf{ \sqrt{169} }}

\mapsto{ \sf{ \sqrt{ {(13)}^{2} } }}

\mapsto{ \sf{ 13 \: units}}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

7 0
3 years ago
Please help!<br> 40 POINTS for you PLUS A THANKS (both on answer and profile), 5 STAR and BRAINLIEST
stepladder [879]
Sorry for bad hand writing

3 0
3 years ago
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