Answer:
2/7
Step-by-step explanation:
The quotient is ...

A common factor of -8 can be cancelled from numerator and denominator.
Answer:
The number of different lab groups possible is 84.
Step-by-step explanation:
<u>Given</u>:
A class consists of 5 engineers and 4 non-engineers.
A lab groups of 3 are to be formed of these 9 students.
The problem can be solved using combinations.
Combinations is the number of ways to select <em>k</em> items from a group of <em>n</em> items without replacement. The order of the arrangement does not matter in combinations.
The combination of <em>k</em> items from <em>n</em> items is: 
Compute the number of different lab groups possible as follows:
The number of ways of selecting 3 students from 9 is = 

Thus, the number of different lab groups possible is 84.
Answer:
Step-by-step explanation:
Given that in a genetics experiment on peas, one sample of offspring contained 376 green peas and 117 yellow peas.
Total no of peas = 376+117=493
No of green peas = 376
Probability of selecting a green pea =
Yes it is reasonably close to 3/4 = 0.75 since difference is only 0.0127 negligible.
(^3-^2+2)D=0
D^2+D^2+2D=0
2D^2+2D=0
a = 2; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·2·0
Δ = 4
D1=−b−Δ√2aD2=−b+Δ√2a
Δ−−√=4√=2
D1=−b−Δ√2a=−(2)−22∗2=−44=−1
D2=−b+Δ√2a=−(2)+22∗2=04=0