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Natasha2012 [34]
3 years ago
6

Before each football game, a coin is flipped to decide who will be on offense and defense. If the last twelve coin tosses result

ed in tails, which is most likely to happen on the next toss? A. most likely heads B. most likely tails C. each result is equally likely to occur
Mathematics
2 answers:
Studentka2010 [4]3 years ago
7 0
C. Each result is equally likely to occur
ololo11 [35]3 years ago
5 0

Answer:

C. each result is equally likely to occur

Step-by-step explanation:

There are only two options, heads or tails. And they both have a 50% chance.

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Divide.
Nataliya [291]

Answer:

 2/7

Step-by-step explanation:

The quotient is ...

  \dfrac{-16}{-56}=\dfrac{2\cdot8}{7\cdot8}=\boxed{\dfrac{2}{7}}

A common factor of -8 can be cancelled from numerator and denominator.

3 0
3 years ago
2. Lab groups of three are to be randomly formed (without replacement) from a class that contains five engineers and four non-en
Anna11 [10]

Answer:

The number of different lab groups possible is 84.

Step-by-step explanation:

<u>Given</u>:

A class consists of 5 engineers and 4 non-engineers.

A lab groups of 3 are to be formed of these 9 students.

The problem can be solved using combinations.

Combinations is the number of ways to select <em>k</em> items from a group of <em>n</em> items without replacement. The order of the arrangement does not matter in combinations.

The combination of <em>k</em> items from <em>n</em> items is: {n\choose k}=\frac{n!}{k!(n-k)!}

Compute the number of different lab groups possible as follows:

The number of ways of selecting 3 students from 9 is = {n\choose k}={9\choose 3}

                                                                                         =\frac{9!}{3!(9 - 3)!}\\=\frac{9!}{3!\times 6!}\\=\frac{362880}{6\times720}\\ =84

Thus, the number of different lab groups possible is 84.

8 0
3 years ago
In a genetics experiment on​ peas, one sample of offspring contained 376 green peas and 117 yellow peas. Based on those​ results
scZoUnD [109]

Answer:

Step-by-step explanation:

Given that in a genetics experiment on​ peas, one sample of offspring contained 376 green peas and 117 yellow peas.

Total no of peas = 376+117=493

No of green peas = 376

Probability of selecting a green pea =\frac{376}{493} =0.7627

Yes it is reasonably close to 3/4 = 0.75 since difference is only 0.0127 negligible.

5 0
4 years ago
Solve (D^3-D^2-D-2)y=0
allsm [11]

(^3-^2+2)D=0

D^2+D^2+2D=0

2D^2+2D=0

a = 2; b = 2; c = 0;

Δ = b2-4ac

Δ = 22-4·2·0

Δ = 4

D1=−b−Δ√2aD2=−b+Δ√2a

Δ−−√=4√=2

D1=−b−Δ√2a=−(2)−22∗2=−44=−1

D2=−b+Δ√2a=−(2)+22∗2=04=0

8 0
3 years ago
Which of the following statements could be true regarding the bar
Ray Of Light [21]
What are the statements
5 0
3 years ago
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