Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.

Mathematics

1 answer:

juin [17]3 years ago

4 0

Answer:

108 cm^2

Step-by-step explanation:

The lateral surface area of a pyramid is given as

LSA= 1/2×perimeter of the base×slant height

base is hexagon with side 3 cm , therefore, perimeter of the base

=6×3=18 cm

slant height = 12 cm

thus, LSA = 1/2×18×12 = 108 cm^2

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cricket20 [7]

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7 0

3 years ago

Please help meeeeeeeeee

NeX [460]

Answer:

see below

a = 0.66...

b = 0.73

c = 7/8

Step-by-step explanation:

The first two numbers, 0.73 and 0.667, are near the point that is halfway between 0.6 and 0.8. That halfway point is 0.7. The value 0.667 will be below (left) of the halfway point, so is point a. The value 0.73 will be above (right) of the halfway point, so is point b. The remaining value, 7/8, must be point c.

You may know that 7/8 = 0.875, so is nearly halfway between 0.8 and 1.

_____

The attached graph has the points color-coded.

_____

Of course you know that the overline in $0.\overline{6}$ indicates that digit repeats indefinitely. The value 0.667 is the number rounded to 3 decimal places.