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3 years ago

Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.

Mathematics

1 answer:

juin [17]3 years ago

4 0

Answer:

108 cm^2

Step-by-step explanation:

The lateral surface area of a pyramid is given as

LSA= 1/2×perimeter of the base×slant height

base is hexagon with side 3 cm , therefore, perimeter of the base

=6×3=18 cm

slant height = 12 cm

thus, LSA = 1/2×18×12 = 108 cm^2

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3 years ago

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Answer:

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3 years ago

There are 42 sixth-grade students and 60 fifth grade students. The students will be put in to the largest possible equal groups

scoundrel [369]

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3 years ago

A walkway is being constructed using square cement tiles that each have an area of 19.0 ft2. 6 tiles will be lined up end to end

allochka39001 [22]

Answer:

26.3 feet

Step-by-step explanation:

We have to first find the length of the side of each tile.

The area of each tile is 19.2 $ft^2$ .

The area of a square is:

A = $L^2$

where L = length of side

Therefore:

$19.2 = L^2\\\\L = \sqrt{19.2} = 4.38 feet$

6 tiles will be lined end to end to construct the walkway, hence, the length of the walkway is:

6 * 4.38 ≅ 26.3 feet

7 0

3 years ago