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Ivan
3 years ago
6

Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.

Mathematics
1 answer:
juin [17]3 years ago
4 0

Answer:

108 cm^2

Step-by-step explanation:

The lateral surface area of a pyramid is given as

LSA= 1/2×perimeter of the base×slant height

base is hexagon with side 3 cm , therefore, perimeter of the base

=6×3=18 cm

slant height = 12 cm

thus, LSA = 1/2×18×12 = 108 cm^2

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miv72 [106K]
Hello!

The formula for finding area is l × w

If the area is 19 ½ inches and it was 3 ¼ inches wide, then the length will be 19 ½ ÷ 3 ¼ (Area ÷ Width)

19  \frac{1}{2} \div 3  \frac{1}{4}

Change both to improper fraction

19  \frac{1}{2} =   \frac{39}{2}

3  \frac{1}{4} =  \frac{13}{4}

\frac{39}{2} \div  \frac{13}{4}

Keep 39/2
Change ÷ to ×
Flip 13/4 = 4/13

\frac{39}{2} \times  \frac{4}{13} =  \frac{156}{26} = 6

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3 years ago
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2 years ago
Evaluate the following expression:<br>p/-3 + (-8)= -8
aalyn [17]
P/-3+(-8)=-8
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Add 8 to each side
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p/-3+(-8)=-8
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7 0
3 years ago
Can someone please help me?
Citrus2011 [14]

Answer:

A. 14

Step-by-step explanation:

Okay, so the square is 25 and the circle is 39.

For example, if you take out the square from the circle, that leaves the shaded areas.

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3 years ago
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Answer:

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