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3 years ago

Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.

Mathematics

1 answer:

juin [17]3 years ago

4 0

Answer:

108 cm^2

Step-by-step explanation:

The lateral surface area of a pyramid is given as

LSA= 1/2×perimeter of the base×slant height

base is hexagon with side 3 cm , therefore, perimeter of the base

=6×3=18 cm

slant height = 12 cm

thus, LSA = 1/2×18×12 = 108 cm^2

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The ribbon was 3 1/4 inches wide and had an area of 19 1/2 square inches. What is the length of the ribbon? Please Help Will Giv

miv72 [106K]

Hello!

The formula for finding area is l × w

If the area is 19 ½ inches and it was 3 ¼ inches wide, then the length will be 19 ½ ÷ 3 ¼ (Area ÷ Width)

$19 \frac{1}{2} \div 3 \frac{1}{4}$

Change both to improper fraction

$19 \frac{1}{2} = \frac{39}{2}$

$3 \frac{1}{4} = \frac{13}{4}$

$\frac{39}{2} \div \frac{13}{4}$

Keep 39/2
Change ÷ to ×
Flip 13/4 = 4/13

$\frac{39}{2} \times \frac{4}{13} = \frac{156}{26} = 6$

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3 years ago

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2 years ago

Evaluate the following expression:<br>p/-3 + (-8)= -8

aalyn [17]

P/-3+(-8)=-8
p/-3-8=-8
Add 8 to each side
p/-3-8+8=-8+8
p/-3=0
Multiply both side by 3
p/-3(3)=0(3)
p=0
Check:
p/-3+(-8)=-8
Substitute p with 0
0/-3+(-8)=-8
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7 0

3 years ago

Can someone please help me?

Citrus2011 [14]

Answer:

A. 14

Step-by-step explanation:

Okay, so the square is 25 and the circle is 39.

For example, if you take out the square from the circle, that leaves the shaded areas.

39-25=14

14 is your answer.

Cheers!

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3 years ago

Determine whether the ratios are equivalent. 3:8 and 9: 24. are they equivalent or not?

Simora [160]

Answer:

Yes, they are equivalent.

Step-by-step explanation:

9 / 3 = 3

24 / 3 = 8

3:8 is just the simplified version of 9:24. This is due to 9:24 being divided by three, becoming 3:8.

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2 years ago