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Westkost [7]
2 years ago
11

Answer for brainliest

Mathematics
1 answer:
madam [21]2 years ago
6 0

Answer:

c

Step-by-step explanation:

Negative 7 over 10 minus negative 2 over 10 = negative 5 over 10; therefore, the distance from A to B is absolute value of negative 5 over 10 equals 5 over 10 units.

the correct option is C.

(-7/10) - (-2/10)

then add -7/10 + 2/10 which will equal -5/10

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Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
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Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2
8 0
3 years ago
Are the fractions equivalent?
dangina [55]

Answer:

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9.yes

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I hope this helps!

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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