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nordsb [41]
2 years ago
12

On average, Cairo gets 2 millimeters of rainfall per month. Based on this information, how

Mathematics
1 answer:
Luba_88 [7]2 years ago
5 0

Answer:

96 millimeters

Step-by-step explanation:

If you get 2 per month then by 1 year you have 24 (2*12 since there are 12 months in a year). From there multiply by 4 since you are looking for 4 years (24*4)

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3. Describe the type of transformation used to produce​
earnstyle [38]

Answer:

Reflection over the x- axis

Step-by-step explanation:

6 0
2 years ago
If a is directly proportional to b/2 and a=1 when b=10, what is the value of a when b=35
iris [78.8K]
The value of a would be 3.5, as a=1 when b=10 means that a is worth 1/10 of b's value. 
5 0
3 years ago
What is 22% of 50?<br> ОА.<br> ОВ.<br> 28<br> Ос.<br> 22<br> OD. 11
natima [27]

Answer:

11

Step-by-step explanation:

3 0
3 years ago
I need help plsssss...........
ch4aika [34]

Answer:

<h2>A)x=3/2 y=½</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • system of linear equation
  • PEMDAS
<h3>let's solve:</h3>
  • since y is equal to both equation therefore we can substitute the value of y into the other equation
  1. \sf substitute \: the \: value \: of \: y :  \\  \sf  - x + 2 = 3x - 4
  2. \sf add \: x \: to \: both \: sides :  \\  \sf  - x + x + 2 = 3x + x - 4 \\  \sf 4x - 4 = 2
  3. \sf add \: 4 \: to \: both \: sides :  \\  \sf xx - 4 + 4 = 2 + 4 \\ 4x = 6
  4. \sf divide \: both \: sides \: by \: 4 :  \\  \frac{4x}{4}  =  \frac{6}{4}  \\ x =  \frac{3}{2}

let's figure out y

  1. substitute the got value of x into the second equation: y=3*3/2 -4
  2. simplify multiplication:9/2 -4
  3. simplify division:4.5-4
  4. substract:0.5 alternate form:y=½

3 0
3 years ago
Three vectors A, B, C in three-dimensional space satisfy the following properties
wlad13 [49]

Answer:

\frac{7}{8}\pi

Step-by-step explanation:

observe

||a–b+c|| = ||a+b+c||

(a-b+c)² = (a+b+c)²

(a+b+c)² – (a-b+c)² = 0

((a+b+c)+(a-b+c))((a+b+c)–(a-b+c)) = 0

(2a+2c)(2b) = 0

(a+c)b = 0

a•b + c•b = 0

||a||×||b||×cos(π/8) + ||c||×||b||×cos(θ) = 0

\cos(\theta)=-\frac{||a||\times ||b|| \times \cos(\frac{\pi}{8})}{||c||\times ||b||}=-\cos(\frac{\pi}{8})\\ \theta=\frac{7}{8}\pi

3 0
3 years ago
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