We have the following information:
first urn: 6 green balls and 3 red ones
total: 6 + 3 = 9
second urn: 3 green, 3 white and 3 red
total: 3 + 3 + 3 = 9
third urn: 6 green, 1 white and 2 red
total: 6 + 1 + 2 = 9
a) A green ball is more likely to be obtained, since there are more green balls than red balls, which makes the probability higher.
b) probability of drawing a green, red and white ball.
first urn:
green = 6/9 = 66.66%
red = 3/9 = 33.33%
white = 0/9 = 0%
second urn:
green = 3/9 = 33.33%
red = 3/9 = 33.33%
white = 3/9 = 33.33%
third urn:
green = 6/9 = 66.66%
red = 2/9 = 22.22%
white = 1/9 = 11.11%
c) it would be chosen where the probability of drawing green would be the highest, which means that it would be possible both in the first and in the third ballot box, the probability is equal 66.66%
d) without a green ball, the third ballot box would look like this:
5 green balls, 2 red balls and 1 white ball, with a total of 8.
The probability of drawing would be:
green = 5/8 = 62.5%
red = 2/8 = 25%
white = 1/8 = 12.5%
Answer:
1 is the right reason
Step-by-step explanation:
Make 6 triangles. each triangle is 24 units it is 144 units
Answer:
A
Step-by-step explanation:
The only side that you dont have to use the Pythagorean theorem is LQ and that measure is 2. So A is the correct answer.
Answer:
1001.35
Step-by-step explanation:
Assuming
n
=
5
for which sum to be found.
We know sum of geometric series up to
n
th term is
S
n
=
a
1
⋅
r
n
−
1
r
−
1
Here
a
1
=
0.11
,
r
=
9.5
,
n
=
5
∴
S
5
=
a
1
⋅
r
5
−
1
r
−
1
=
0.11
⋅
9.5
5
−
1
9.5
−
1
≈
1001.35
[Ans]