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AnnyKZ [126]
3 years ago
13

A doctor wants to know if her patients are happy with her. She decides to survey a sample of her clients. What method would be b

est for choosing a random sample that is a fair representation of her patients?
Mathematics
2 answers:
Leokris [45]3 years ago
8 0
The method should be to a<span>ssign numbers to each patient and then use a random number generator to choose one hundred patients to survey. </span>
Rudik [331]3 years ago
7 0

Answer:

A doctor wants to know if her patients are happy with her. She decides to survey a sample of her clients.

To choose a random sample from her patient list, she must choose the patients randomly. For this she can assign numbers to her patients like 1 to 300 and then randomly draw numbers from the list either by herself or by number generator. She can choose 30 to 40 percent of her patients randomly for conducting this survey.

This type of random selection is completely random and non biased.

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For 1948 Men's :Interquartile range is 1.5, Median is 58.3

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Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

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47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

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