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kvv77 [185]
3 years ago
12

The teachers’ editions of a statistics textbook sell for $150 each, and students’ editions of the book sell for $50 each. Which

function can be used to find the average cost per book if two teachers’ editions and x students’ editions are purchased?
Mathematics
2 answers:
Novay_Z [31]3 years ago
7 0

Answer:

(300 + 50x)/(2 + x)

Step-by-step explanation:

Let the cost of teachers' edition books be t

Let the cost of students' edition books be s

So t = 150; s = 50

Then the total cost of 2 teachers' editions and x students' editions is 2t + sx = 2 × 150 + 50x = 300 + 50x.

The total number of books is 2 + x.

So the average cost per book is (300 + 50x)/(2 + x)

ycow [4]3 years ago
7 0

Answer:

the answer is D.

Step-by-step explanation:

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In each box is a step in the process of solving a max/min problem like the one in Question 8. Number these steps in order (1-8)
Dmitriy789 [7]

Answer:

The steps are numbered below

Step-by-step explanation:

To solve a maximum/minimum problem, the steps are as follows.

1. Make a drawing.

2. Assign variables to quantities that change.

3. Identify and write down a formula for the quantity that is being optimized.

4. Identify the endpoints, that is, the domain of the function being optimized.

5. Identify the constraint equation.

6. Use the constraint equation to write a new formula for the quantity being optimized that is a function of one variable.

7. Find the derivative and then the critical points of the function being optimized.

8. Evaluate the y-values of the critical points and endpoints by plugging them into the function being optimized. The largest y- value is the global maximum, and the smallest y-value is the global minimum.

8 0
3 years ago
In one grade of 150 students, the ratio of boys to girls
juin [17]

You idiot you answered your own question!

7 0
3 years ago
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krok68 [10]
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5 0
4 years ago
Read 2 more answers
Is 68 prime because i am doing homework and im stuck on this and it is very hard so help me please
BlackZzzverrR [31]

If  68  is a prime number, then the only factors it has are  1  and  68.
If it has any other factors besides  1  and  68, then it's NOT prime.

Right away, without any higher math, you can look at just the last digit
in 68 .  The last digit is '8'.  That tells you that '68' is an even number,
and THAT tells you that '2' must be one of its factors.  So '68' is not a
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The factors of  68  are  1,  2,  4,  17,  34, and  68 .    

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8 0
3 years ago
Read 2 more answers
2x^{2} +4x+1=0 <br> Solve for x.
Viefleur [7K]
2x^2 + 4x + 1 = 0

2x^2 + 4x + 1 - 1 = 0 - 1

2x^2 + 4x = -1

X(2x + 4) = -1

X = -1.

2x + 4 = -1
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2x/2 = -5/2
X = -5/2.

I believe these are the solutions. If not you can use the quadratic formula to solve for the roots, solutions.
7 0
3 years ago
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