Answer is C. 
First start by subtracting the exponents from top to bottom
let's start with a so a^2 - a^-2 2 - (-2) = 4
Now B: b^-3 - b^2 so -3 - 2 = -5
This leaves you with a^4 b^-5
However you cannot have a negative exponent so B must cross over and move to the bottom to become positive
Don't forget about the squared outside the parentheses. Both exponents must be multiplied by two to get 8 and 10
Answer:
No
Step-by-step explanation:
For a point to be a solution of a system of equations, it has to work for both equations in said system. For this particular point, it doesn't fit into both.
12=5(2)+2
12=10+2
12=12
4(2)-12=0
8-12=0
-4=0
The second equation doesn't work out.
Answer:
y^4
Step-by-step explanation:
2y^10, 5y^4, 6y^5
We first need to find the factors of each term
2y^10 = 2*yyyyyyyyyy
5y^4 = 5yyyy
6y^5 = 3*2 yyyyy
The greatest common factor is the largest term that appears in all the terms
The greatest common factor is yyyy = y^4