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mylen [45]
3 years ago
13

DNA Mutations

Chemistry
1 answer:
vitfil [10]3 years ago
6 0

Answer:

Explanation:

A

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Write an ionic equation for the reaction of acetic acid with sodium ethoxide, and specify whether the equilibrium favors startin
Elina [12.6K]
<h2>Acetic Acid + Sodium ethoxide ⇄ Butyric Acid + Sodium Hydroxide</h2>

Explanation:

An ionic equation for the reaction of acetic acid with sodium ethoxide is as follows -

  • Reactants -

       Acetic Acid and Sodium ethanolate (sodium ethoxide)

  • Products -

       Butyric Acid and Sodium hydroxide

Hence,

     Acetic Acid + Sodium ethoxide ⇄ Butyric Acid + Sodium Hydroxide

     CH_3COOH + C_2H_5ONa ⇄ CH_3COOC_2H_5 + NaOH

  • Weak acids and bases have low energy than strong acids and bases.
  • The chemical equilibria shift the reaction side with the species having lower energy.
  • Given reaction is an acid-base reaction in which the equilibrium favors the starting material that means it will go to the side of the weakest acid that is acetic acid is weaker than butyric acid.
6 0
3 years ago
The atomic number of magnesium (mg) is 12. this is also the number of which of the following
Rzqust [24]
The answer is protons.
8 0
2 years ago
Find the pHpH of a solution prepared from 1.0 LL of a 0.15 MM solution of Ba(OH)2Ba(OH)2 and excess Zn(OH)2(s)Zn(OH)2(s). The Ks
charle [14.2K]

Answer:

pH  = 13.09

Explanation:

Zn(OH)2 --> Zn+2 + 2OH-   Ksp = 3X10^-15

Zn+2 + 4OH-   --> Zn(OH)4-2   Kf = 2X10^15

K = Ksp X Kf

  = 3*2*10^-15 * 10^15

  = 6

Concentration of OH⁻ = 2[Ba(OH)₂] = 2 * 0.15 = 3 M

                Zn(OH)₂ + 2OH⁻(aq)  --> Zn(OH)₄²⁻(aq)

Initial:           0             0.3                      0

Change:                      -2x                     +x

Equilibrium:               0.3 - 2x                 x

K = Zn(OH)₄²⁻/[OH⁻]²

6 = x/(0.3 - 2x)²  

6 = x/(0.3 -2x)(0.3 -2x)

6(0.09 -1.2x + 4x²) = x

0.54 - 7.2x + 24x² = x

24x² - 8.2x + 0.54 = 0

Upon solving as quadratic equation, we obtain;

x = 0.089

Therefore,

Concentration of (OH⁻) = 0.3 - 2x

                                    = 0.3 -(2*0.089)

                                  = 0.122

pOH = -log[OH⁻]

         = -log 0.122

          = 0.91

pH = 14-0.91

     = 13.09

4 0
3 years ago
How is milk souring a chemical change?
hichkok12 [17]
Because the chemicals are different
7 0
3 years ago
2. Why can we eliminate the claim you circled?
Luda [366]

Answer: theres no image or claim

7 0
3 years ago
Read 2 more answers
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