Answer:
1. 57.5%
2. 27.89 g
Explanation:
1. Determination of the percentage of sodium in sodium hydroxide.
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Mass of Na in NaOH = 23 g
Percentage of Na = mass of Na / Molar mass of NaOH × 100
Percentage of Na = 23/40 × 100
Percentage of Na = 57.5%
2. Determination of the mass of sodium in 48.5 g of sodium hydroxide.
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Mass of Na in NaOH = 23 g
Total mass of NaOH = 48.5 g
Mass composition of Na = mass of Na / Molar mass of NaOH × Total mass
Mass composition of Na = 23/40 × 48.5
Mass composition of Na = 27.89 g
Answer:
- option B
- option A
Explanation:
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If points E and D are midpoints of triangle ABC, then the perimeter of the triangle is:AB + BC + CA = 48, or:
3 t + 3 t + 4 t + 4 t + 7 t + 6 = 4821 t = 48 - 621 t = 42t = 42 : 21t = 2Answer: A. 2.
Answer:
d. 3 signals: a singlet, a doublet, and a septet
Explanation:
In this case, we can start with the structure of 
. When we draw the molecule we will obtain <u>2-methoxypropane</u> (see figure 1).
In 2-methoxypropane we will have three signals. The signal for the 
groups in the left, the 
and the in the right. Lets analyse each one:
-) in the right
In this carbon, we dont have any hydrogen as neighbors. Therfore we will have <u>singlet</u> signal in this carbon.
-)
In this case, we have 6 hydrogen neighbors ( the two methyl groups in the left). So, if we follow the <u>n + 1 rule</u> (where n is the amount of hydrogen neighbors):
For this carbon we will have a <u>septet</u>.
-) in the left
In this case we have only 1 hydrogen neighbor (the hydrogen in
). So, if we use the n+1 rule we will have:
We will have a doublet
With all this in mind the answer would be:
<u>d. 3 signals: a singlet, a doublet, and a septet
</u>
<u />
See figure 2 to further explanations
Answer:
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