Answer:
Liming reagent in the given reaction is oxygen.
Explanation:
Mass of octane = 12.85 g
Mass of oxygen = 7.46 g
Molar mass of octane = 114.23 g/mol
Molar mass of oxygen = 32




According to the reaction, 2 moles of octane requires 25 moles of O2
so, 0.1125 moles of octane requires
of oxygen.
but only 0.2331 mol of oxygen is present.
Hence, oxygen is the limiting reagent
Anything in group 18. These are the noble gases, known for having the stable octet in the outermost electron shell (with the exception of Helium). These elements include Neon, Xenon, and Radon, to name a few.
Remark
The balance numbers in front of the chemicals tell you how to set up the proportion to solve your question
For every 2 moles Na only 1 mole of Cl2 is required.
Equation
2 moles Na:1 mole Cl2 :: x moles Na:4 moles Cl2
Solution
2/1 = x/4 Cross multiply
2*4 = x*1
8 = x
Conclusion
8 moles of Na will be used. <<< Answer
The question is incomplete, the complete question is;
Arrange the isotopes of chlorine and sulfur in order of decreasing number of neutrons. Rank the isotopes from most to fewest neutrons. To rank items as equivalent S-33,S-36,S-34,Cl-35,S-32,Cl-37
The isotopes of sulphur arranged in order of decreasing number of neutrons is; S-36, S-34, S-33, S-32. The isotopes of chlorine arranged in order of decreasing number of neutrons is; Cl-37, Cl-35.
Isotopes are atoms of the same element having different mass numbers but the same atomic number.
Isotopes differ in their number of neutrons. The number of neutrons is obtained by subtracting the atomic number of an isotope from its mass number.
The number of neutrons in the isotopes of sulphur are;
S-36 (20 neutrons)
S-34 (18 neutrons)
S-33 (17 neutrons)
S-32 (16 neutrons)
The number of neutrons in the isotopes of chlorine are;
Cl-37 (20 neutrons)
Cl-35 (18 neutrons)
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I believe this is a double replacement. As you can see none of the chemical symbols are missing, there just "replaced".