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3 years ago

What part of the water is affected by a wave in deep water

Chemistry

2 answers:

Nostrana [21]3 years ago

8 0

wave base is the most affected by a wave in deep water

k0ka [10]3 years ago

5 0

There is a thing called "wave action". In a submarine, you can feel wave action down to about 100 feet or so. Below 100 feet, the wave action is insignificant. The reason is buoyancy. As a wave passes over you, in effect the water gets deeper, there is more over your head, and alternately, as a trough passes over you, the water gets shallower. This alternating change in depth causes you to bob up and down like a cork. This all changes as the water gets shallower. A wave is really a moving pressure front. As the water gets shallower, the speed increases, which is why a wave "breaks" as it approaches a shore line but is invisible further away. The Tsunami in Japan that traveled across the Pacific was invisible until it reached the shallower water off the Pacific Coast where it did significant damage. What was a few INCHES in the middle of the Pacific became several FEET at the shoreline, all because the water went from very deep to very shallow. I was in submarines in the Navy for 21 years of service. Wave action is a very real thing and being at periscope depth in a hurricane is like a roller coaster as the boat gets thrown around.

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What type of indications would be shown if an igneous rock cooled quickly?

Nana76 [90]

It's actually C because the rock cooled fast

6 0

3 years ago

Need help with this.

Jobisdone [24]

Answer:

18.2 g.

Explanation:

You need to first figure out how many moles of nitrogen gas and hydrogen (gas) you have. To do this, use the molar masses of nitrogen gas and hydrogen (gas) on the periodic table. You get the following:

0.535 g. N2 and 1.984 g. H2

Then find out which reactant is the limiting one. In this case, it's N2. The amount of ammonia, then, that would be produced is 2 times the amount of moles of N2. This gives you 1.07 mol, approximately. Then multiply this by the molar mass of ammonia to find your answer of 18.2 g.

5 0

2 years ago

Consider the reaction below.

Law Incorporation [45]

Answer:

First choice: 0.042

Explanation:

Given decomposition reaction:

1PCl₅ (g) ⇄ 1PCl₃ + 1Cl₂(g)

Equilibrium constant:

$K_{eq}=\frac{[PCl_3]^1[Cl_2]^1}{[PCl_5]^1}$

Stoichiometric coefficients and powers equal to 1 are not usually shown as they are understood, but I included them in order to shwow you how they intervene in the equilibrium expressions: each concentration is raised to a power equal to the respective stoichiometric coefficient in the equilibrium equation.

So, your calculations are:

$K_{eq}=\frac{(0.020M)(0.020M)}{0.0095M}=0.042M$

6 0

3 years ago

Consider four different samples: aqueous LiBr , molten LiBr , aqueous AgBr , and molten AgBr . Current run through each sample p

Charra [1.4K]

Answer:

a) Aqueous LiBr = Hydrogen Gas

b) Aqueous AgBr = solid Ag

c) Molten LiBr = solid Li

c) Molten AgBr = Solid Ag

Explanation:

a) Aqueous LiBr

This sample produces Hydrogen gas, because the H+ (conteined in the water) has a reduction potential higher than the Li+ from the salt. Therefore the hydrogen cation will reduce instead of the lithium one and form the gas.

b) Aqueous AgBr

This sample produces Solid Ag, because the Ag+ has a reduction potential higher than the H+ from the water. Therefore the silver cation will reduce instead of the hydrogen one and form the solid.

c) Molten LiBr

In a molten binary salt like LiBr there is only one cation present in the cathod. In this case the Li+, so it will reduce and form solid Li.

c) Molten AgBr

The same as the item above: there is only one cation present in the cathod. In this case the Ag+, so it will reduce and form solid Ag.

6 0

3 years ago

Question 3

meriva

Answer:

We are dependent on plants and plants need CO2 from enviromen

Explanation:

8 0

2 years ago

Read 2 more answers