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s2008m [1.1K]
3 years ago
5

ben helps his dad make chicken soup. their recipe makes 15 cups of soup. if they each eat 2 cups and freeze the rest will the le

ftovers fit in a 64 ounce container? 1 cup = 8 ounces
Chemistry
1 answer:
VikaD [51]3 years ago
5 0
No ,8 x 15 is 90,90-4 is 86
You might be interested in
I don’t understand how to do this
djverab [1.8K]
Carbon dioxide is a carbon atom and two oxygen atoms, therefore CO2

For the others, they are hydrocarbons.
The first part of the name is determined by how many carbon atoms there are. The second part, is by the type. Alcohol, Alkane, Alkene, alkynes, acid, esters, amides.

7 0
3 years ago
What are the compounds empirical and molecular formulas
Liono4ka [1.6K]

Answer:

The empirical formula is the simplest ratio of atoms while molecular is the actual formula.

Explanation:

Empirical Formula is the simplest ratio of atoms present in the compound.

The molecular formula shows the actual number of atoms present in the compound.

For example, CH is the empirical formula and C6H6 is the molecular formula of benzene.

5 0
2 years ago
If all other variables remain unchanged, what happens to the output force when the area of the input piston is doubled?
mars1129 [50]

Answer:

1250N

Explanation:

This question is based on pascal's Law.

So By Pascal's Law

 =  

therefore  =force on input piston =25N

                  = Force or weight on output person.

therefore after putting the values we get,

= (25x 1500)/30

    =1250N

3 0
3 years ago
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0
2 years ago
Which groups on the periodic table contain metalloids? Groups 1–2 Groups 3–12 Groups 13–16 Groups 17–18
agasfer [191]
The correct answer is groups 13-16
6 0
3 years ago
Read 2 more answers
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