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4 years ago

5

ben helps his dad make chicken soup. their recipe makes 15 cups of soup. if they each eat 2 cups and freeze the rest will the le

ftovers fit in a 64 ounce container? 1 cup = 8 ounces

1 answer:

VikaD [51]4 years ago

5 0

No ,8 x 15 is 90,90-4 is 86

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Energy for this ecosystem originally comes from

erma4kov [3.2K]

Answer:

sunlight is the answer i think

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3 years ago

Urgent 25 points!!

LekaFEV [45]

Answer:

A. Yes, Amanda find the number of moles of NaCl correctly.

B. 0.73 M.

Explanation:

<em>A. Did Amanda find the number of moles of NaCl correctly? If not, explain. </em>

Yes, Amanda find the number of moles of NaCl correctly.

The relation to find the no. of moles of NaCl is:

<em>No. of moles (n) of NaCl = mass/molar mass.</em>

mass of NaCl = 32.0 g, molar mass of NaCl = 58.45 g/mol.

∴ No. of moles (n) of NaCl = mass/molar mass = (32.0 g)/(58.45 g/mol) = (32.0 g NaCl)*(1 mol of NaCl)/(58.45 g NaCl) = 0.547 mol ≅ 0.55 mol.

<em>B. What does Amanda need to do next to calculate the molarity of the NaCl solution? Show your work for full credit.</em>

<em></em>

Molarity is the no. of moles of solute dissolved in a 1.0 liter of a solution.

∴ M = (no. of moles of NaCl)/(volume of solution (L)) = (0.55 mol)/(0.75 L) = 0.73 M.

5 0

4 years ago

Isotopes ____________ the atomic mass of an element because they have a ____________ number of neutrons. a. disregard, constant

3241004551 [841]

Is B. The number of the atomic mass can increase or decrease because the number of neutrons is different.

7 0

3 years ago

The mass of an average blueberry is 0.75 g and the of am automoblie is 2.0 x 10 to the 3 Kg. Find the number of automobiles whos

Paul [167]

Answer : The number of automobiles needed are, $2.26\times 10^{17}$

Explanation :

First we have to calculate the mass of blueberries.

As, 1.0 mole of blueberries contains $6.022\times 10^{23}$ blueberries

So, 0.75 grams of blueberries contains $0.75g\times 6.022\times 10^{23}=4.52\times 10^{23}g$ blueberries

Mass of blueberries = $4.52\times 10^{23}g$

Now we have to calculate the number of automobiles needed.

Number of automobiles needed = $\frac{4.52\times 10^{23}g}{2.0\times 10^{3}kg}$

Number of automobiles needed = $\frac{4.52\times 10^{23}g}{2.0\times 10^{3}\times 10^{3}g}$

Number of automobiles needed = $2.26\times 10^{17}$

Thus, the number of automobiles needed are, $2.26\times 10^{17}$

8 0

3 years ago

Rank the compounds by the ease with which they ionize under sn1 conditions. rank the compounds from easiest to hardest. to rank

marysya [2.9K]

The rate of Formation of Carbocation mainly depends on two factors'

1) Stability of Carbocation:
The ease of formation of Carbocation mainly depends upon the ionization of substrate. If the forming carbocation id tertiary then it is more stable and hence readily formed as compared to secondary and primary.

2) Ease of detaching of Leaving Group:
The more readily and easily the leaving group leaves the more readily the carbocation is formed and vice versa. In given scenario the carbocation formed is tertiary in all three cases, the difference comes in the leaving group. So, among these three substrates the one containing Iodo group will easily dissociate to form tertiary carbocation because due to its large size Iodine easily leaves the substrate, secondly Chlorine is a good leaving group compared to Fluoride. Hence the order of rate of formation of carbocation is,

R-I > R-Cl > R-F

B > C > A

3 0

3 years ago