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Ira Lisetskai [31]
3 years ago
8

Solve for m in E=1/2mv²+mgh

Mathematics
2 answers:
liraira [26]3 years ago
7 0
E= \frac{1}{2}mv^2+mgh \ \ / \cdot 2\\ \\ 2 \cdot \frac{1}{2}mv^2+ 2\cdotmgh = 2\cdot E\\ \\ mv^2+2mgh= 2E \\ \\m(v ^2+2gh)= 2E \\ \\ m=\frac{2E}{v ^2+2gh}


solong [7]3 years ago
5 0
E= \frac{1}{2} mv^2+mgh\ /\cdot2\\\\2E=mv^2+2mgh\\\\2E=m(v^2+2gh)\ /:(v^2+2gh)\\\\m= \frac{2E}{v^2+2gh}
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We need to read the graph to see which are the two quantities related and how these are related.

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If you want to learn more about graphs, you can read:

brainly.com/question/4025726

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