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3 years ago

In the figure points A B C D and E are collinear. If AE = 38 and BD = 15

Mathematics

1 answer:

fredd [130]3 years ago

6 0

Answer:

D. 30.5

Step-by-step explanation:

Given that A, B, C, D, and E are collinear,

AE = 38,

BD = 15, since segment BC = CD = DE, therefore

BD = ⅔ of BE

15 = ⅔*BE (substitution)

Solve for BE

Multiply each side by 3

15*3 = ⅔*BE*3

45 = 2*BE

Divide both sides by 2

45/2 = BE

22.5 = BE

BE = 22.5

Find AB:

AB + BE = AE (segment addition postulate)

AB + 22.5 = 38 (Substitution)

AB = 38 - 22.5 (Subtracting 22.5 from each side)

AB = 15.5

Find length of segment AD:

AB + BD = AD (segment addition postulate)

15.5 + 15 = AD (Substitution)

30.5 = AD

AD = 30.5

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Amelia has 3 gallons of paint .Mason have 10 quarts .How many more pints of paint does AMELIA have then mason.

Ber [7]

Answer:

4 Pints

Step-by-step explanation:

According to the scenario, calculations are as follows,

As we know, 1 gallon = 8 Pints

1 Quarts = 2 Pints

So, Amelia = 3 Gallons = 3 × 8 Pints = 24 Pints

Mason = 10 quarts = 10 × 2 Pints = 20 Pints

So, Number of more pints Amelia has = Amelia number of pints - Mason number of pints

= 24 pints - 20 pints

= 4 Pints

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3 years ago

- The water level of a lake fell by 13 inches during

bezimeni [28]

Answer:

r = - 13 / 15 inches/week

Step-by-step explanation:

The numerator is 13

and the denominator is 15, then we have

r = - 13 / 15 inches/week

r < 0 since the water level of the lake fell

6 0

4 years ago

Kim finds a 1-meter tree branch and marks it off in thirds and fifths. She then breaks the branch along all the markings and rem

True [87]

Answer:

3/5

Step-by-step explanation:

We want to find the fraction of the original branch that remains, so we will assume a length of the branch in order to make our calculation easier.

Since Kim marks it off in thirds and fifths, let's find the least common multiple of 3 & 5.

Least common multiple of 3 & 5 is 15.

Thus,let's make the length of the branch to be 15-meter long.

Now, if the branch is 15 m long, considering the markings of thirds and fifths, the branch would be cut at:

3, 5, 6, 9, 10, 12 meters.

We are told that She then breaks the branch along all the markings and removes one piece of every distinct length. Thus;

Distinct lengths are;

3 metres

5 - 3 = 2 metres

10 - 9 = 1 meter

Total she removes = 3 + 2 + 1 = 6 meters.

Total remaining is;

15 - 6 = 9 meters

Expressing this as a fraction of the original branch gives:

9/15

Divide both numerator and denominator by 3 to get; 3/5

7 0

3 years ago

Given a triangle MTN, prove that

cupoosta [38]

Answer:

$\angle m + \angle t + \angle n = 180$

Step-by-step explanation:

Required

Show that:

$\angle m + \angle t + \angle n = 180^o$

To make the proof easier, I've added a screenshot of the triangle.

We make use of alternate angles to complete the proof.

In the attached triangle, the two angles beside $\angle m$ are alternate to $\angle t$ and $\angle n$

i.e.

$\angle 1 = \angle t$

$\angle 2 = \angle n$

Using angle on a straight line theorem, we have:

$\angle 1 + \angle m + \angle 2 = 180$

Substitute values for (1) and (2)

$\angle t + \angle m + \angle n = 180$

Rewrite as:

$\angle m + \angle t + \angle n = 180$ -- proved

5 0

3 years ago

19. The bases of a trapezoid are 8 and 22 and the trapezoid's area is 135. Find the height

julia-pushkina [17]

Answer: 9

Step-by-step explanation:

A=(a+b)/2 *h

135= 30/2* h

135= 15 * h

135/15= h

9=h

8 0

3 years ago

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