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Eva8 [605]
3 years ago
15

In the figure points A B C D and E are collinear. If AE = 38 and BD = 15

Mathematics
1 answer:
fredd [130]3 years ago
6 0

Answer:

D. 30.5

Step-by-step explanation:

Given that A, B, C, D, and E are collinear,

AE = 38,

BD = 15, since segment BC = CD = DE, therefore

BD = ⅔ of BE

15 = ⅔*BE (substitution)

Solve for BE

Multiply each side by 3

15*3 = ⅔*BE*3

45 = 2*BE

Divide both sides by 2

45/2 = BE

22.5 = BE

BE = 22.5

Find AB:

AB + BE = AE (segment addition postulate)

AB + 22.5 = 38 (Substitution)

AB = 38 - 22.5 (Subtracting 22.5 from each side)

AB = 15.5

Find length of segment AD:

AB + BD = AD (segment addition postulate)

15.5 + 15 = AD (Substitution)

30.5 = AD

AD = 30.5

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What is the value of the expression below when w = 3. 4w^2 - 7w - 8
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Step-by-step explanation:  The prime factorization of  4320   is

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To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 4320   =  √ 2•2•2•2•2•3•3•3•5   =2•2•3•√ 30   =

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So now we are looking at:

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Two real solutions:

w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757

or:

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