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3 years ago

Volume of triangular prism base 18in, height 9in, length 24in

Mathematics

1 answer:

padilas [110]3 years ago

8 0

Answer:

1944 in³

Step-by-step explanation:

We are given;

Dimensions of a triangular prism;

Base is 18 inches
Length is 9 inches, and
Length is 24 inches

We are required to determine the volume of the prism

To answer the question we need to know that the volume of a triangular prism is given by;

Volume = 0.5 × Width × height × Length

Therefore;

Volume = 0.5 × 18 in × 9 in × 24 in

= 1944 in³

Thus, the volume of the triangular prism is 1944 in³

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Shkiper50 [21]

Answer:

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3 years ago

Which property was applied to create this equivalent expression? 7 x (5 6 x) right-arrow (7 x 5) 6 x the commutative property on

krok68 [10]

The option (B) is correct. Associative property was applied to create the given expression.

Given expression is 7x+(5+6x) rightarrow (7x+5)+6x.

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The commutative property didn't satisfy the given expression.

Now, check the given expression by associative property.

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The distributive property didn't satisfy the given expression.

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8 0

2 years ago

Read 2 more answers

Use the quadratic formula to solve each equation.

Elden [556K]

Answer:

1) $x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}$

$x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}$

2) $x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}$

$x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}$

3) $p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}$

$p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}$

4) $y_1 = \frac{-3 - 9}{4}=-3$

$y_2 = \frac{-3 + 9}{4}= \frac{3}{2}$

Step-by-step explanation:

The quadratic formula is given by:

$x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

We can use this formula in order to solve the following equations:

1. x^2 − 2x = 12 → a = 1, b = −2, c = −12

For this case if we apply the quadratic formula we got:

$x = \frac{-(-2) \pm \sqrt{(-2)^2 -4(1)(-12)}}{2(1)}$

$x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}$

$x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}$

2. 1/2x^2 − 6x = 2 → a = 1 / 2, b = −6, c = −2

For this case if we apply the quadratic formula we got:

$x = \frac{-(-6) \pm \sqrt{(-6)^2 -4(1/2)(-2)}}{2(1/2)}$

$x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}$

$x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}$

3. 2p^2 + 8p = 7 → a = 2, b = 8, c = −7

For this case if we apply the quadratic formula we got:

$p = \frac{-(8) \pm \sqrt{(8)^2 -4(2)(-7)}}{2(2)}$

$p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}$

$p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}$

4. 2y^2 + 3y − 5 = 4 → a = 2, b = 3, c = −9

For this case if we apply the quadratic formula we got:

$y = \frac{-(3) \pm \sqrt{(3)^2 -4(2)(-9)}}{2(2)}$

$y_1 = \frac{-3 - 9}{4}=-3$

$y_2 = \frac{-3 + 9}{4}= \frac{3}{2}$

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4 years ago

Please answer correctly !!!! Will mark Brianliest !!!!!!!!!!!!!

NARA [144]

Answer:

2261,9 cm³

Step-by-step explanation:

First, you need to find the area of the base:

$A=\pi r^2$

A=36 $\pi$ cm²

Now let's multiply it for the height:

36π cm² × 20 cm = 720π cm³

= 2261,9 cm³

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3 years ago

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