Answer: AA similarity theorem.
Step-by-step explanation:
Given : AB ∥ DE
Prove: ΔACB ≈ ΔDCE
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
Also ∠C ≅ ∠C using the reflexive property.
Therefore by AA similarity theorem , ΔACB ≈ ΔDCE
- AA similarity theorem says that if in two triangles the two pairs of corresponding angles are congruent then the triangles are similar .
Answer:
MT is congruent to MS
Step-by-step explanation:
<span>The percentile score would most likely be 97.5, Hope this helps!! :D
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<span>5×70=5× 7 tens
=35 tens =350
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Answer:
66.6% or 0.66
Step-by-step explanation:
82% or 0.82 of All households have cable TV.
X = The number of households in a group of 6, that have cable TV.
You wish to find the proportion or percentage of groups for which EXACTLY 4 of 6 households will have cable TV.
82% of 6 is = 4.92
Approximately 4.92 out of 6 households, have cable TV.
Using this figure, you can now find out what % of 6 will give you 4.
Cross multiply:
0.82 - 4.92
M - 4
M = (4×0.82) ÷ 4.92 = 3.28÷4.92 = 0.666
Hence, 66.6% of 6 households, have cable TV. In other words, exactly 4 households (X=4) have cable TV.
To test, you can find what 66% of 6 is. You will get 4.
