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The solution contains 39.4% of LiF. Assume that the solution is 100ml. The molar mass of LiF is 25.939, the amount of LiF in mole would be: 100ml * 1g/ml * 39.4%/ 25.939g/mol= 1.52 mol LiF
Then the mass of the water would be: 100gram- 39.4g= 60.6g
If the molar mass of water is 18.015 the mole of the water would be: 60.6g/ 18.015g/mol= 3.36 mol
.
The mole fraction would be:1.52 mol/ 1.52+3.36= 0.339
Boyle's Law
P1V1 = P2V2
1.8 atm * 2.5 L = P2 * 1.2 L
1.8 atm * 2.5 L / 1.2 L = P2
3.75 atm = P2
Using significant digits, the answer is 3.8 atm
Answer:
2.09 atm
Explanation:
Step 1: Given and required data
- Volume of the vessel (V): 25.0 L
We won't need the data of water and uncombusted fuel, since the partial pressures are independent of each other.
Step 2: Calculate the number of moles (n) corresponding to 60.0 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
60.0 g × 1 mol/44.01 g = 1.36 mol
Step 3: Calculate the partial pressure of CO₂
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T/ V
P = 1.36 mol × (0.0821 atm.L/mol.K) × 468.2 K/ 25.0 L = 2.09 atm
