Answer:
I'd there and pictures?? can put the list
Answer:
0.0095 moles of acid were neutralized by the antiacid
Explanation:
The antiacid is a base that neutralize the acid in stomach. To find the moles of acid neutralized we need to find the moles of acid added initially. This acid is added in excess, then, the moles of NaOH added reacts to neutralize the moles of acid in excess. The difference between initial moles of HCl and moles of NaOH needed to titrate the excess = Moles of HCl that were neturalized by the antiacid as follows:
<em>Moles HCl added:</em>
42.00mL = 0.04200L * (0.250mol/L) = 0.0105 moles HCl
<em>Moles NaOH to titrate the excess:</em>
10.00mL = 0.01000L * (0.10mol/L) = 0.0010 moles NaOH = Moles HCl in excess.
<em>Moles of acid that were neutralized:</em>
0.0105 moles - 0.0010 moles =
<h3>0.0095 moles of acid were neutralized by the antiacid</h3>
M(NaCl)=55.84 g
m(H₂O)=157.2 g
m(solution)=m(NaCl)+m(H₂O)
w(NaCl)=100m(NaCl)/m(solution)=100m(NaCl)/(m(NaCl)+m(H₂O))
w(NaCl)=100*55.84/(55.84+152.7)=26.78%
Answer:
C
Explanation:
the rain does help the soli it can make bacteria
Answer:
a. 0.66 atm
Explanation:
Pi = 750 torr = 0.99 atm. Pf = ?
Vi = 400 ml Vf = 600ml
Using PiVi = PfVf
Then 400ml × 0.99atm = Pfatm × 600ml
Solving for Pf, we have,
Pf = (400ml × 0.99atm)/600ml
Pf = 0.66atm
