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noname [10]
3 years ago
13

PLEASE HELP i’ll mark brainliest ( reporting fake answers)

Chemistry
1 answer:
kherson [118]3 years ago
6 0

Delta S reaction= Delta S products- Delta S reactants

don't forget to mulitiply by coefficients

also

here is a really slow way to do it

you know the moles of gas increased

so Delta S is positive

so its B or D

then just do the units digit to see which one match up

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Which best describes the effect of jj Thomson discovery
beks73 [17]
JJ Thomson discovered electrons using the cathode ray. Electrons are negatively charged particles that orbit around the nucleus of an atom. Finding out that there was a negative charge to balance out the positive charge. This later helped develop Hund's Rule and the Pauli Exclusion Principle.
7 0
3 years ago
Using your knowledge of symbols, determine which compound listed must contain both copper and oxygen.
Gemiola [76]

Answer:

The correct option is Malachite which has both copper nd oxygen.

Explanation:

As we the symbol of copper is Cu while the symbols of oxygen is O. As the chemical formula of malachite is Cu₂CO₃(OH)₂. So it has Cu as well as O.

Glucose has only oxygen but no copper

Chalcopyrite has copper but no oxygen

Calcite has oxygen but no copper.

So correct answer is only malachite.

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5 0
3 years ago
What is a process by which long-term carbon is released into the atmosphere
LekaFEV [45]

Answer:

The carbon cycle

Or

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6 0
4 years ago
Read 2 more answers
Under laboratory conditions of 25.0 degrees C and 99.5 kPa, what is the maximum number of liters of ammonia that could be produc
Minchanka [31]

Answer:

Volume of ammonia 3 L.

Explanation:

Given data:

Temperature = 25°C ( 25+273= 298 k)

Pressure = 99.5 kpa (99.5/101 = 0.98 atm)

Volume of nitrogen = 1.50 L

Volume of ammonia = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Moles of nitrogen:

PV = nRT

n = PV/RT

n = 0.98 atm × 1.50 L / 0.0821 atm. L/mol. K × 298 K

n = 1.47 /24.5 /mol

n = 0.06 mol

Now we will compare the moles of nitrogen with ammonia.

                         N₂        :        NH₃

                          1          :          2

                           0.06   :        2×0.06 = 0.12 mol

Volume of ammonia:

PV = nRT

V = nRT/P

V = 0.12 mol× 0.0821 atm. L/mol. K × 298 K/  0.98 atm

V = 2.9 atm. L /0.98 atm

V = 3 L

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3 years ago
Name two solutions in a galvanic cell
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0.3 M FeCl2, solution two is 1.7 M MgCl2.
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